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fgiga [73]
3 years ago
7

The hourly wage increases each employee receives each year depends on the number of years of service. Every three years of servi

ce means an increase of $0.50 per hour. So, employees that have been with the company for less than three years can expect to receive an increase of $0.50 per hour. Employees that have been with the company for at least three years, but less than six years can expect an increase of $1.00 per hour. Employees that have been with the company for at six years, but less than nine years, receive an increase of $1.50 per hour. And, employees of at least nine years, but less than twelve years receive an increase of $2.00 per hour. Choose a function to represent this scenario
Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

________{0.50 if x < 3

________{1.00 if 3 ≤ x < 6

f(x) = ____{1.50 if 6 ≤ x < 9

________{2.00 if 9 ≤ x < 12

Step-by-step explanation:

Given the information above :

Less than Employees = $0.5 increase per hour

Atleast 3 but less than 6 years employees = $1.00 increase per hour

Atleast 6 but less than 9 years employees = $1.50 increase per hour

Atleast 9 but less than 12 years employees = $2.00 increase per hour

The information above can be written as a piecewise function :

________{0.50 if x < 3

________{1.00 if 3 ≤ x < 6

f(x) = ____{1.50 if 6 ≤ x < 9

________{2.00 if 9 ≤ x < 12

The constraints is represented in the piecewise function above with x being the number of years since employee has been in service.

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Suppose JK bisects angle LJM. The measure of angle LJK = (-10x + 3) and the measure of KJM = (-x + 21)º. Find the measure of ang
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-10x + 3 =  -x + 21

+ 10 x            +10x
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3 years ago
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4 years ago
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4 years ago
Without a calculator how would you solve this?
mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6

=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}

\bigstar\  (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}

\bigstar\  \bigstar\  (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}

\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702

\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6

0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0

\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0

\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702

8 0
3 years ago
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