Let's start with the length. All you need to do is multiply is by 1/500.
You could also find the decimal equivalent to 1/500.
1/500= .002
200×.002= .4
So length of the model is .4 ft.
The width:
.002×140=.28
The width of the model is .28 ft.
The length of the model is .4 ft and the width of the model is .28 ft.
Assuming that the angles are congruent, then y = 29.
4y - 8 = 79 + y
4y = 87 + y Add 8 to both sides
3y = 87 Subtract y from both sides
y = 29
What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?
Romashka-Z-Leto [24]
Answer:
The Interquartile range is 10.
Step-by-step explanation:
First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.
So, 23-13=10
The Answer will be 10, the interquartile range is 10.
Hope this helps!
Hello!
The corresponding angle theorem states that if two parallel lines are cut my a transversal, then the corresponding angles are congruent. Therefore, the correct answer is:
B. ∠2 = ∠6
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