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Anna35 [415]
3 years ago
7

I reallyyyy do neeed some help with this ?? I keep getting them wrong ;(

Mathematics
1 answer:
Aleks [24]3 years ago
4 0
The angle adjacent to angle 3 = 45  The figure is a kite and the long diagonal cuts the top angle in 2 Therefore < 3 = 45 degrees.
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Hello: 
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7 0
3 years ago
Ron is 5 years older than twice his cousins pats age. The sum of their ages is less than 35. What is the grates age pat could be
Anestetic [448]

The answer is 7 because if you multiply 7 with 5 than it will equal 35

Hope it helps


7 0
3 years ago
Scores of an IQ test have a​ bell-shaped distribution with a mean of 100 and a standard deviation of 17. Use the empirical rule
-BARSIC- [3]

Answer:

(a) 95% of people have an IQ score between 66 and 134.

(b) 32% of people have an IQ score of less than 83 or greater than 117​.

(c) 16% of people have an IQ score greater than 117.

Step-by-step explanation:

We are given that scores of an IQ test have a​ bell-shaped distribution with a mean of 100 and a standard deviation of 17.

Let X = <u><em>scores of an IQ test</em></u>

SO, X ~ Normal(\mu=100, \sigma^{2} = 17^{2})

The z-score probability distribution for the normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

<u>Now, the empirical rule states that;</u>

  • 68% of the data values lie within 1 standard deviation from the mean.
  • 95% of the data values lie within 2 standard deviations from the mean.
  • 99.7% of the data values lie within 3 standard deviations from the mean.

(a) The percentage of people having an IQ score between 66 and 134 is given by;

     z score for 66 =  \frac{X-\mu}{\sigma}  =  \frac{66-100}{17}  = -2

     z score for 134 =  \frac{X-\mu}{\sigma}  =  \frac{134-100}{17}  = 2

This means that the percentage of people having an IQ score between 66 and 134 is 95%.

(b) Firstly, we have to find the percentage of people having an IQ score between 83 and 117;

     z score for 83 =  \frac{X-\mu}{\sigma}  =  \frac{83-100}{17}  = -1

     z score for 117 =  \frac{X-\mu}{\sigma}  =  \frac{117-100}{17}  = 1

This means that the percentage of people having an IQ score between 83 and 117 is 68%.

This means that the percentage of people having an IQ score of less than 83 or greater than 117 = 100% - 68% = 32%.

(c) In the above part, we find that there are 32% of the values that have an IQ score of less than 83 or greater than 117.

This means that half of this will be less than 83 and half of this will be greater than 117.

So, the percentage of people having an IQ score greater than 117​ = \frac{32\%}{2} = 16%.

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The question says; If a left-handed individual were selected from this group, what is the probability the individual would be ri
Oksanka [162]
The third is the correct answer because when you reduced 25/65 you will get 5/13
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What are the solutions of −1 ≤ x − 3 &lt; 4?
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The solution would be x>2
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