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madam [21]
3 years ago
15

4x^2 = − 9x − 4 quadratic

Mathematics
1 answer:
Goryan [66]3 years ago
4 0

Answer:

Yes, see the explanation.

Roots:

x = \frac{63}{8}, or x= -10

Step-by-step explanation:

A quadratic fomrual in standard form is;

ax^(2) + bx + c = 0

The given equation:

4x^2 = -9x - 4

Maniplate the equation using inverse operations

4x^2 = -9x - 4

-4x^2    -4x^2

0 = -4x^2 - 9x - 4

Yes, this is a quadratic equation, because it fits the requirement of being able to be written in standard form.

Now find its roots:

-4x^2 -9x - 4 = 0

remember,

x = \frac{(-b) +- (\sqrt{b^{2} - 4ac }) }{2a}

Substitute in the given values

x= \frac{(-(-9)) +- (\sqrt{(-9)^{2} - 4(-4)(-4)}) }{2(-4)}

Simplify,

x = \frac{9 +- (\sqrt{5184}) }{-8}

x = \frac{9 +- 72}{-8}

x = \frac{63}{8}

or

x= -10

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Answer:

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Step-by-step explanation:

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Hope this helps, have a nice day/night! :D

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jek_recluse [69]

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Hello from MrBillDoesMath!


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Discussion; I think the problem statement should actually be to rewrite <u>this</u> equation:

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Note  the power of "x-5" is 4 in the first term and is 2 in the second term. That is, the power of x-5 in the first terms is double, or the square, of the (x-5) power occurring in the second term. This suggest the substitution u = (x-5)^2.  Then the equation can be rewritten as

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Regards, MrB


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