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kogti [31]
3 years ago
15

If there are 45 guests at the party, predict how many would choose a gift card?

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0

Answer:

Since there is a 50-50 chance of a person at the party choosing a gift card, and since there can only be 1 of 2 outcomes, we can assume that there will either be more people choosing a gift card than not, or there will be more people not choosing a gift card than are. So, that means that there would be 23 people (more or less) choosing a gift card and 22 people (more or less) not choosing a gift card or vice-versa.

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Solve for b. ab+c=d<br> B=a+c/d<br> B=a/(c-d)<br> B=(d-c)/a
vekshin1

Answer:

b = (d-c)/a

Step-by-step explanation:

ab+c=d

Subtract c from each side

ab+c-c=d-c

ab = d-c

Divide by a

ab/a = (d-c)/a

b = (d-c)/a

3 0
3 years ago
Jade solved the following equation:
sergey [27]

step 1 has incorrect justification

4 0
3 years ago
In order to ensure efficient usage of a server, it is necessary to estimate the mean number
juin [17]

Answer:

a. [36.19;39.21]

b. Reject the null hypothesis. The population mean of users that are connected at the same time is greater than 35.

Step-by-step explanation:

Hello!

Your study variable is,

X: "number of users of one server at a time"

The objective is to estimate the mean, for this, a sample of n=100 times was taken and the standard deviation S= 9.2 and the sample mean is X[bar]= 37.7 were calculated.

You need to study the population mean, for this you need your variable to have at least normal distribution. Since you don't have information about its distribution, but the sample is big enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample mean X[bar] to normal:

X[bar]≈N(μ;σ²/n)

a. With this approximation, you can construct the 90% Confidence Interval using the approximate Z

[X[bar] ± Z_{1-\alpha /2} * S/√n]

Z_{1-\alpha /2} = Z_{0.95} = 1.64

[37.7± 1.64* 9.2/√100]

[36.19;39.21]

b. You need to test if the population mean is greater than 35 with a level of significance of 1%.

The hypothesis is:

H₀: μ ≤ 35

H₁: μ > 35

α: 0.01

This is a one-tailed test so you have only one critical level (right tail):

Z_{1\alpha } = Z_{0.99} = 2.33

This means that if the value of the calculated statistic is equal or greater than 2.33 you will reject the null Hypothesis.

If the value is less than 2.33 you will support the null hypothesis.

The statistic is:

Z=<u> X[bar] - μ </u>= <u> 37.7 - 35 </u> = 2.93

       S/√n           9.2/10

The value 2.93 > 2.33, so you reject the null hypothesis. This means that the population mean of users that are connected at the same time is greater than 35.

<u><em>Note: </em></u><em>To make the decision using the interval calculated on a), the hypothesis should have been two-tailed and the confidence and significance levels complementary.</em>

I hope it helps!

7 0
3 years ago
Given: Ray BC bisects angle ABD.
natita [175]

Congruent is the same size and same shape. When a ray bisects an angle, the two newly created angles will be congruent, since the ray went right in the middle of the first angle (so in this case, ABC and DBC will be congruent)

4 0
3 years ago
Read 2 more answers
How to turn 65%into a fraction​
Free_Kalibri [48]

Answer:

65/100

Step-by-step explanation:

Since it is a whole percentage it would be over 100. Since its 65%, it would be 65/100

6 0
3 years ago
Read 2 more answers
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