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azamat
1 year ago
10

2. Invasive weed species can grow quickly. One variety grows up to 1.65 ft per day.

Mathematics
1 answer:
Radda [10]1 year ago
6 0

Invasive weed grows at a rate of 0.0011 ft per minute a day

In the above question, it is given as

Invasive weed grows really fast and the rate of its growth is being provided as follows

The rate at which the weed is growing a day is = 1.65 ft

We need to find the, rate at which this weed is growing per minute

So, to do this, we'll find the growth in 1 min

In 24 hours growth is = 1.65 ft

Conversion factors

We know, 1 hour = 60 minutes

In 1 min growth is = \frac{1.65}{24 . 60}

Here, we have multiplied with 60 in the denominator to convert hours into minutes  

After solving the fraction we'll get

Growth in 1 min of the weed = 0.0011 ft

Hence, Invasive weed grows at a rate of 0.0011 ft per minute a day

To learn more about minute here

brainly.com/question/15600126

#SPJ1

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Answer:

Graphs: 14, 16, and 17 are graphs of proportional relationships. The constants of proportionality are 3/2, -1/4, and 1, respectively.

Missing values: 18: 12; 19: 6; 20: 21; 21: -4; 22: -5; 23: 40.

Step-by-step explanation:

<em>Explanation for Graphs</em>

The graph of a proportional relation is <em>always a straight line through the origin</em>. The graph of 15) is not such a graph, so is not the graph of a proportional relation.

The constant of proportionality is the slope of the line: the ratio of vertical change to horizontal change. In each of these graphs, points are marked so it is easy to count the squares between marked points to determine the amount of change. (One of the marked points in each case is the origin.)

14) The graph goes up 3 for 2 squares to the right, so the slope and constant of proportionality are 3/2.

16) The graph goes down 1 square for 4 squares to the right, so the slope and constant of proportionality are -1/4.

17) The graph goes up 3 squares for 3 squares to the right, so the slope and constant of proportionality are 3/3 = 1.

_____

<em>Explanation for Missing Values</em>

When 3 values are given and you're asked to find the 4th in a proportion, there are several ways you can do it. Here's one that may be easy to remember, especially if you write it down for easy reference when you need it.

Let's call the given values "a", "b", and "c". They can be given in ordered pairs, such as (x, y) = (a, b) = (2, -4), and a missing value from an ordered pair, such as (c, _) = (-6, y). (These are the numbers from problem 18.)

In this arrangement, the "_" is the second value of the second ordered pair, so corresponds to "b", the second value of the first ordered pair. The value "c" is the other half of the ordered pair with a value missing, so it, too, can be said to correspond to the "_".

The solution is the product of these two corresponding values, divided by the remaining given value. That is, for ...

... (a, b) = (c, _)

the unknown value is

... _ = bc/a

___

If the relation is written with the first value missing, the same thing is true: the solution is the product of corresponding values divided by the remaining given value.

... (a, b) = (_, c)

... _ = ac/b

___

This still holds when the pairs are on the other side of the equal sign.

  • For (c, _) = (a, b), the solution is _ = bc/a
  • For (_, c) = (a, b), the solution is _ = ac/b

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18) y = (-6)(-4)/2 = 12

19) x = (4)(24)/16 = 6

20) y = (12)(7)/4 = 21

21) x = (-16)(6)/24 = -4

22) x = (3)(30)/-18 = -5

23) x = (32)(100)/80 = 40

_____

<em>More Formally ...</em>

In more formal terms, the proportional relation can be written as

... b/a = _/c . . . . for (a, b) = (c, _)

Multiplying both sides of this equation by c gives ...

... bc/a = c_/c

Simplifying gives

... bc/a = _

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... a/b = _/c . . . . for (a, b) = (_, c)

... _ = ac/b

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