To find the area of a sector of a circle use the next formula:
![A=\frac{\theta}{360º}*\pi *r^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B%5Ctheta%7D%7B360%C2%BA%7D%2A%5Cpi%20%2Ar%5E2)
As the given circle has a outside angle 90º (it is not part of the sector of the circle) subtract the 90º from 360º (total angle of a circle) to find the angle of the sector:
![\theta=360º-90º=270º](https://tex.z-dn.net/?f=%5Ctheta%3D360%C2%BA-90%C2%BA%3D270%C2%BA)
Find the area of the sector with angle 270º:
![\begin{gathered} A=\frac{270º}{360º}*3.14*(11in)\placeholder{⬚}^2 \\ \\ A=0.75*3.14*121in^2 \\ \\ A=284.955in^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D%5Cfrac%7B270%C2%BA%7D%7B360%C2%BA%7D%2A3.14%2A%2811in%29%5Cplaceholder%7B%E2%AC%9A%7D%5E2%20%5C%5C%20%20%5C%5C%20A%3D0.75%2A3.14%2A121in%5E2%20%5C%5C%20%20%5C%5C%20A%3D284.955in%5E2%20%5Cend%7Bgathered%7D)
Then, the approximate area of the given sector of a circle is 284.955 square inches
Answer:
Step-by-step explanation:
a) The objective of the study is test the claim that the average gain in the green fees , lessons or equipment expenditure for participating golf facilities is less than $2,100 under the claim the null and alternative hypothesis are,
H₀ : μ = $2,100
H₀ : μ < $2,100
B) Suppose you selects α = 0.01
The probability that the null hypothesis is rejected when the average gain is $2,100 is 0.01
C) For α = 0.01
specify the rejection region of a large sample test
At the given level of significance 0.01 and the test is left-tailed then rejection level of a large-sample = < - 1.28
Calculate the mean of this data set: 12, 35, 44, 74, 23, 49, 45, 18, 90, 56, 84,
Blababa [14]
Well, here is the mean of ur data collected 48.181818...
R = 16 according to the problem, so the total amount of income will be:
$20*16 + $15*(40 - 16)
= $320 + <span>$15*(24)
= </span>$320 + <span>$360
= $680
that is the income, but the expenses are $275 so the total revenue is the subtraction of those two
total revenue = $680 - $275
= $405</span>
1/12 is the answer i think