Using PEMDAS, You know that you have to multiply first so 3*2 is 6. Than you have to add 6+4 which gives you 10... So there for 10 is your answer....
Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
I get 433 divided by 8 .... 433/8
Answer:
B x = sqrt(48)
Step-by-step explanation:
Half of the bottom side measures 4.
4^2 + x^2 = 8^2
16 + x^2 = 64
x^2 = 48
x = sqrt(48)
Answer: B x = sqrt(48)
Answer:
x=-23
Step-by-step explanation:
-3.8x-5.9x=223.1
-9.7x=223.1
x=223.1/-9.7
x=-23
