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pashok25 [27]
3 years ago
13

If you were present 120 days out of 124 days what percent were you present

Mathematics
1 answer:
emmainna [20.7K]3 years ago
5 0

Answer:

~96.6

Step-by-step explanation:

120/124 is 30/31 or 60/62 or 96.6/99.82

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What is the perimeter of a rectangle with a length of (x^2+x) and a width of (2x^2+3x)
Mazyrski [523]

Answer:

Perimeter = 6x² + 8x

Step-by-step explanation:

Perimeter = 2(length + width)

perimeter = 2((x²+x)+(2x²+3x))

perimeter = 2(x²+2x² + x+3x)

perimeter = 2(3x² + 4x)

perimeter = 2*3x² + 2*4x

perimeter = 6x² + 8x

5 0
3 years ago
Which choice is the equation of a line that passes through the point (–6, –2) and is perpendicular to the line represented by th
kobusy [5.1K]

Answer:

  B.  y = 1/3x

Step-by-step explanation:

The slope of the given line is -3, so the slope of the perpendicular line will be the negative reciprocal of that: -1/(-3) = 1/3. This eliminates choices A and C.

We can find the y-intercept (b) if we use the given point values in the equation ...

  y = 1/3x +b

we get ...

  -2 = (1/3)(-6) +b

  -2 = -2 +b . . . simplify

  0 = b . . . . . . . add 2

So, the equation of the perpendicular line through the given point is ...

  y = 1/3x . . . . matches choice B

_____

<em>Alternate solution method</em>

You can try the given point in the given equations. You will find that only the equation of choice B will work.

7 0
3 years ago
Step 3a: Calculating the average rate
Alex73 [517]

9514 1404 393

Answer:

  a) average rate = (total distance)/(total time)

  b) Rave = 2·R1·R2/(R1 +R2)

  c) cheetah's average rate ≈ 50.91 mph

Step-by-step explanation:

a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...

  First leg distance: AB = 70·t1   ⇒   t1 = AB/70

  Second leg distance: AB = 40·t2   ⇒   t2 = AB/40

The average rate is the ratio of total distance to total time:

  average rate = (AB +AB)/(t1 +t2)

  average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)

  average rate = 560/11 = 50 10/11 . . . mph

__

No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.

b) For two rates over the same distance (as above), the average is their harmonic mean:

  average rate = 2r1·r2/(r1+r2)

__

c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.

4 0
3 years ago
Solve: g^2x+1=g^3x-2<br> x=?
Schach [20]

Answer:

the answer you will be looking for is g^2x - g^3x = -3

Step-by-step explanation:

as much as I would like to, I'm really not that great at explaining things

6 0
2 years ago
Solve the equation negative 3X +9 equals three(2x+3) + 3(x-4) + 1
timofeeve [1]

Answer:

1

Step-by-step explanation:

-3x+9=3(2x+3)+3(x-4)+1

Distributive property in the parenthesis

-3x+9=6x+9+3x-12+1

Combine Like Terms

-3x+9=9x-2

Get the x’s on one side

-3x+9=9x-2

+3.  +2    +3. +2

11=11x

Divide by 11 on both sides

11/11=1

5 0
3 years ago
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