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balu736 [363]
2 years ago
15

Will give 60 points and brainliest

Mathematics
2 answers:
elixir [45]2 years ago
7 0

In order to find the value of x, we can write the following statements and reasons:

Triangle PQR:

1. Statement: PS = PS

Reason: Reflexive property of equality

2. Statement: angle PSQ is congruent to angle PSR

Reason: Given

3. Statement: SQ is equal to SR

Reason: Given:

4. Statement: Triangle PSQ is congruent to triangle PSR

Reason: Case SAS of congruency

5. Statement: PQ is congruent to PR, so PR = 8

Reason: Corresponding sides of congruent triangles

Quadrilateral VSTU:

1. Statement: VT = VT

Reason: Reflexive property of equality

2. Statement: angle SVT is congruent to angle UVT

Reason: Given

3. Statement: angle VST is congruent to angle VUT

Reason: Given

4. Statement: Triangle VST is congruent to triangle VUT

Reason: Case AAS of congruency

5. Statement: ST = TU

Reason: Corresponding sides of congruent triangles

So we have 5z = 2z + 3. Solving for z, we have z = 1, so ST = 5z = 5

Katen [24]2 years ago
6 0
I am not sure what you mean, but x=4
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Standard notation 9x10 to the 2 power
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In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
1. 4x-8+2x+-5x+x²-3=<br> 2.3x+5x=<br> 3.2r+4+3x-2=<br> 4.3x-2y-x+5y=<br> 5.2y²-8y³+5y-5y²+4y³=
Marrrta [24]
1. 4x - 8 + 2x + (-5x) + x^2 - 3 = 4x - 8 + 2x - 5x + x^2 - 3...now, we just combine like terms....lets group them...it will be easier ...x^2 + (4x + 2x - 5x ) - 8 - 3 = x^2 + x - 11

2. 2x + 5x = 8x

3. 2r + 4 + 3x - 2 = 3x + 2r + (4 - 2) = 3x + 2r + 2

4. 3x - 2y - x + 5y = (3x - x) + (5y - 2y) = 2x + 3y

5. 2y^2 - 8y^3 + 5y - 5y^2 + 4y^3 = (4y^3 - 8y^3) + (2y^2 - 5y^2) + 5y =
    -4y^3 - 3y^2 + 5y
3 0
3 years ago
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