Question

A pyramid-shaped roof has a slant height of 16 ft and its square base is 40 ft wide. How much roofing material is needed to

Answer 1

Answer:

1280ft²

Step-by-step explanation:

To find the total surface area of a square pyramid, we find the area of the square base and add it to the area of the four triangular faces.

The area of the square base is

${40}^{2} = 1600 {ft}^{2}$

The area of the four triangular faces is

$= 4 \times \frac{1}{2} \times 40 \times 16 = 1280 {ft}^{2}$

In the context of this problem , the base will not be roofed, therefore the 1280 ft² of material is needed to cover the roof