Given that th<span>e coordinates of the vertices of △DEF are D(2, −1) , E(7, −1) , and F(2, −3) and the coordinates of the vertices of △D′E′F′ are D′(0, −1) , E′(−5, −1) , and F′(0, −3) .
Notice that the y-coordinates of the pre-image and that of the image are the same, which means that there is a reflection across the y-axis.
A refrection across the y-axis results in the change in sign of the x-coordinates of the pre-image and the image while the y-coordinate of the image remains the same as that of the pre-image.
A refrection across the y-axis of </span>△DEF with vertices D(2, −1) , E(7, −1) , and F(2, −3)
will result in and image with vertices (-2, -1), (-7, -1) and (-2, -3) respectively.
Notice that the x-coordinate of the final image △D′E′F′ with vertices <span>D′(0, −1) , E′(−5, −1) , and F′(0, −3) is 2 units greater than the vertices of the result of recting the pre-image across the y-axis.
This means that the result of refrecting the pre-image was shifted two places to the right.
Therefore, </span>the sequence of transformations that maps △DEF to △D′E′F′ are reflection across the y-axis and translation 2 units right.
Answer:
(2,7) x=2 y=7
Step-by-step explanation:
Answer:
they all as a group will be doing 1/3 of the work. There are 4 robots.
how much will each individual robot be doing from the total work?
well, how many times does 4 go into 1/3?
Step-by-step explanation:
The amount of money each of Mr Mokwebo 's two sons; Tokelo and Refentse will get is R116 and R95 respectively.
<h3>How to write and solve equation:</h3>
- Amount needed to buy chocolate = R253
- Tokelo's money = x
- Refentse's money = x - 21
Total amount needed = Tokelo's money + Refentse's money
253 = x + (x - 21)
253 = x + x - 21
253 = 2x - 21
253 - 21 = 2x
232 = 2x
divide both sides by 2
x = 232/2
x = 116
Therefore,
Tokelo's money = x = R116
Refentse's money = x - 21
= 116 - 21
= R95
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82 is the answer now sub to pooi thegreat on yt
