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kari74 [83]
3 years ago
6

Plz answer me will mark as brainliest read full question

Mathematics
1 answer:
Musya8 [376]3 years ago
6 0

Answer:83 -->17-->103-->43-->7-->1

Have a good day

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Let R = {0, 1, 2, 3} be the range of h (x ) = x - 7. The domain of h inverse is
KonstantinChe [14]
Hello,


As h(x) is a bijection,
range(h(x))=dom(h^(-1)(x))={0,1,2,3}

Answer C
8 0
3 years ago
Read 2 more answers
I’ll mark you brainlist I’ll mark you brainlist show work
Alex787 [66]

Answer:

2=p

Step-by-step explanation:

-5p+7=5p-13

+5p +5p

7=10p-13

+13 +13

20=10p

÷10 ÷10

2=p

5 0
3 years ago
Lacy draws a diamond from a standard deck of 52 cards. Without replacing the first card, she then proceeds to draw a second card
Viktor [21]

Answer:

a) i) No

ii) Probability of drawing a diamond and then spade without replacement is 0.0637.

b) i) Yes

ii) Probability of drawing a diamond and then spade with replacement is 0.0625

Step-by-step explanation:

Part a) Without replacement:

i) Are these events independent?

No, because the both events are dependent. because a card taken out of the deck is not replaced back before taking out the other card so the chances of event occur change.

ii) Determine the probability of drawing a diamond and then a spade without replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after taking diamond = 52 -1 =51

Spades = 13

Probability of drawing a spade  = 13/51

Probability of drawing a diamond and then spade = 13/52 * 13/51

= 169/2652

=0.0637

So, Probability of drawing a diamond and then spade without replacement  is 0.0637

Part b) With replacements

i) Are these events independent?

Input Yes or No:

Yes, these events are independent because a card taken out of the deck is replaced back before taking out the other card so the chances of event occur doesn't change.

ii) Determine the probability of drawing a diamond and then a spade with replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after replacing diamond = 52

Spades = 13

Probability of drawing a spade  = 13/52

Probability of drawing a diamond and then spade = 13/52 * 13/52

= 169/2704

=0.0625

So, Probability of drawing a diamond and then spade with replacement is 0.0625

7 0
3 years ago
State when the following equations and inequalities will be true and when they will be false.
-BARSIC- [3]

' 36 = 9k ' is not an inequality.  It's an <u>equality</u>, usually called an <em><u>equation</u></em>.

It's true whenever 'k' is 4, and false at any other time.

(You can determine that simply by dividing each side of the equation by 9.)


6 0
3 years ago
Factor 64-112w+49w^2
photoshop1234 [79]
49w² -112w + 64
first, you have to find 2 numbers that add up to equal -112, but also multiply together to get a product of 3136 (49 * 64)

two numbers that add to -112 and multiply to equal 3136 is -56 and -56
we can add them into the equation by putting them in for -112x

49w²-56w-56w+64

we now look at what the first 2 numbers have in common and what the last two numbers have in common
49w² and -56w both have w and 7 in common so we can divide 7w
7w(7w -8)
-56w and 64 both have -8 in common so we can divide by -8
-8(7w-8)
now we take the 2 numbers on the outside and bring down the numbers in the brackets

(7w-8)(7w-8)
(7w-8)²

7 0
3 years ago
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