Example :
u have an endpoint at (6,5)......ad the midpoint is (4,2)....find the other endpoint.
midpoint formula : (x1 + x2) / 2, (y1 + y2) / 2
one endpoint (6,5)....x1 = 6 and y1 = 5
other endpoint (x,y)...x2 = x and y2 = y
sub into the formula
m = (6 + x) / 2, (5 + y) / 2
okay, so the midpoint is (4,2)....so ur x value will equal 4
(6 + x) / 2 = 4...multiply both sides by 2
6 + x = 4 * 2
6 + x = 8
x = 8 - 6
x = 2 <==
midpoint is (4,2)....so the y value will equal 2
(5 + y) / 2 = 2 ...multiply both sides by 2
5 + y = 2 * 2
5 + y = 4
y = 4 - 5
y = -1 <==
so ur other endpoints are (2,-1)
Answer:
3.1
Step-by-step explanation:
ok so
4.7j-6.8k J=5 k=3 plug in the values
4.7(5)-6.8(3)
23.5-20.4
3.1
Answer:
B
Step-by-step explanation:
Answer:
A) f(x) = x^2 +8(x+2)
Step-by-step explanation:
We will start by putting y=0
0 = x^2+8(x+2) -Apply distributive property
0 = x^2+8x+16
0=(x+4)(x+4)
0=x+4, 0=x+4
x=-4
There is only one zero, and that is x=-4
Brainiest would be appreciated.
Answer:
The 95% confidence interval is "87.94, 91.86".
Step-by-step explanation:
The given values are:
Sample batches,
n = 25
Sample mean concentration,
= 89.9 mg
Amount of chemical,
σ = 5
α = 0.05
The critical value from Z table will be:
= 
= 
= 
Now,
The confidence interval will be:
= 
On substituting the values, we get
= 
= 
= 
Lower limit will be:
= 
= 
Upper limit will be:
= 
= 
