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3 years ago

I need help with the wuestion

Mathematics

1 answer:

givi [52]3 years ago

5 0

Answer:

What is the question?

Step-by-step explanation:

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Get Geordi Through the Door geometry worksheet

Murljashka [212]

Answer:

what does that even mean'

Step-by-step explanation:

3 0

3 years ago

Show your work:<br><br> Express 160 pounds (lbs) in kilograms (kg). Round to the nearest hundredths.

andrew-mc [135]

Answer:

160 lbs = 72.57kg

Step-by-step explanation:

This can be solved as a rule of three problem.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

Unit conversion problems, like this one, is an example of a direct relationship between measures.

Each lb has 0.45kg. How many kg are there in 160lbs. So:

1lb - 0.45kg

160 lbs - xkg

$x = 0.45*160$

$x = 72.57$ kg

160 lbs = 72.57kg

4 0

3 years ago

What is the answer to my question, 45x27?

TiliK225 [7]

Answer:

1,215

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

(c). Under a set of controlled laboratory conditions, the size of the population P of a certain bacteria culture at time t (in s

Bezzdna [24]

(i) Since P(t) gives the population of the culture after t seconds, the population after 1 second is

P(1) = 3•1² + 3e¹ + 10 = 13 + 3e ≈ 21.155

In Mathematica, it's convenient to define a function:

P[t_] := 3t^2 + 3E^t + 10

(E is case-sensitive and must be capitalized. Alternatively, you could use Exp[t]. You can also specify that the argument t must be non-negative by entering a condition via P[t_ ;/ t >= 0], but that's not necessary.)

Then just evaluate P[1], or N[P[1]] or N <at symbol> P[1] or P[1] // N to get a numerical result.

(ii) The average rate of change of P(t) over an interval [a, b} is

(P(b) - P(a))/(b - a)

Then the ARoC between t = 2 and t = 6 is

(P(6) - P(2))/(6 - 2) ≈ 321.030

In M,

(P[6] - P[2])/(6 - 2)

and you can also include N just as before.

(iii) You want the instantaneous rate of change of P when t = 60 (since 1 minute = 60 seconds). Differentiate P :

P'(t) = 6t + 3e^t

Evaluate the derivative at t = 60 :

P'(60) = 6•60 + 3e⁶⁰ = 360 + 3e⁶⁰

The approximate value is quite large, so I'll just leave its exact value.

In M, the quickest way would be P'[60], or you can differentiate and replace (via ReplaceAll or /.) t with 60 as in D[P[t], t] /. t -> 60.

5 0

3 years ago

Which number line best shows the position of square root of 7?

Brrunno [24]

The number line would go from (-10 to 10)

4 0

3 years ago