Answer:
Your in Pacyber aren't you? Mr. Breux class? Anyway the answer is (0,-4)
Step-by-step explanation:
The y intercept is (0,-4)
The answer to your question is 2
No, GCF means greatest common factor, meaning the largest number than can be divided into the number. 2 would be the lowest common factor or LCF.
EX. 200 & 440. In this case the GCF would be 40, but the LCF would be 2 because they are both even numbers
Answer:

Step-by-step explanation:
Given

Required
Find 
From the attachment:
The measure of
is calculated using the following expression:

Where
-- right-angled.
The expression becomes



<h2>
<u>Requi</u><u>red</u><u> Answer</u><u> </u><u>:</u><u>-</u></h2>
Given system of linear equations are ,
And we need to find the Solution of the linear equation . So let's Firstly number the equations .
<u>→</u><u> </u><u>Multipl</u><u>ying</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>by</u><u> </u><u>3</u><u> </u><u>,</u>
=> 3 ( x + y ) = 2*3
=> 3x + 3y = 6
<u>→</u><u> </u><u>Addin</u><u>g</u><u> </u><u>the</u><u> </u><u>two</u><u> </u><u>equations </u><u>,</u><u> </u>
=> 3x + 3y -3y + y = 6 + 2
=> 4y = 8
=> y = 8/4
=> y = 2
<u>→</u><u> </u><u>Put</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>in</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>,</u>
=> x + y = 2
=> x + 2 = 2
=> x = 2- 2
=> x = 0
<h3>
<u>★</u><u> </u><u>Hence</u><u>
the required solution is ( 0 , 2 ) .</u></h3>