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sineoko [7]
2 years ago
8

Select all expressions shown that are equivalent to

Mathematics
1 answer:
Murrr4er [49]2 years ago
4 0

Answer:

A.  and C.

if you simplify the expressions, you will see which ones are equal to the expression given

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F(x)= x^2-8x+15
mash [69]
If I'm reading your equations correctly, they are:f(x)=x2-8x+15g(x)=x-3h(x)=f(x)/g(x)The domain of a function is the set of all possible inputs, what we can plug in for our variable.The largest two limitations on domains (other than explicit limitations, like in piecewise functions) are radicals and rational functions. With radical expressions we know that we CANNOT take an even root of a negative number. I don't see that problem here. With rationals we know that we CANNOT divide by zero. So the question becomes, when does h(x) ask us to divide by zero? When is the denominator of h(x) zero?Since the denominator of h(x) is g(x), we cannot let g(x) equal zero. So when does that happen? when x-3=0 or when x=3. I hope you see here that if x=3, then g(x)=0, and so h(x)=f(x)/0, which we CANNOT do. The domain of h(x) is all real numbers not equal to 3. There is more going on here. If you had factored f(x) first, you could have written h(x) in a confusing way:h(x)=( f(x) ) / ( g(x) )h(x)= ( (x-5)(x-3) ) / (x-3) Right here, it looks like (x-3) will cancel out from the top and bottom of your fraction. It does, in a way. The graph of h(x) will behave exactly like the line y=x-5, except that it has a hole in it at x=3 (check this! it's cool!)SOOO, the takeaway is that it is better to determine limitations on your domain BEFORE over-simplifying your equations.
6 0
3 years ago
Simplify:
Scrat [10]
Factoring is decomposing a higher powered expression into a lower powered expressions that are multiplied together. Since (a-b)(a^2+ab+b^2) is lower powered than a^3-b^3, (a-b)(a^2+ab+b^2) is more simplified. 
The Difference of Cubes formula shows up frequently in mathematics courses and should be memorized. 
 The formula for factoring the difference of cubes is (a^3 - b^3)= (a-b)(a^2+ab+b^2). It works because if (a-b)(a^2+ab+b^2) is multiplied it out, then it becomes a^3 - b^3. This was probably originally determined by trial and error a long time ago. 
 Since x is cubed and 8 is 2^3 it factors with the Difference of Cubes Formula.  (x^3-2^3)=(x-2)(x^2+2x+2^2)=(x^2+2x+4)
8 0
4 years ago
Someone please help me
Ronch [10]

Answer:

you have it correct as b

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve each equation 15-5(4x-7)=50
andre [41]

Answer:

Simplifying

15 + -5(4x + -7) = 50

Reorder the terms:

15 + -5(-7 + 4x) = 50

15 + (-7 * -5 + 4x * -5) = 50

15 + (35 + -20x) = 50

Combine like terms: 15 + 35 = 50

50 + -20x = 50

Add '-50' to each side of the equation.

50 + -50 + -20x = 50 + -50

Combine like terms: 50 + -50 = 0

0 + -20x = 50 + -50

-20x = 50 + -50

Combine like terms: 50 + -50 = 0

-20x = 0

Solving

-20x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-20'.

x = 0.0

Simplifying

x = 0.0

3 0
3 years ago
Which statement is true? 6 is 3 times as many as 2
Fudgin [204]

Statement A: 6 is 3 times as many as 2

2 x 3 = 6

Hope I helped ,please give brainliest!

5 0
4 years ago
Read 2 more answers
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