. Show that square of any positive integer can not be of form 7q + 3 or 7q+5or 7q + 6, for any integer q
1 answer:
Step-by-step explanation:
7q + 3 or 7q+5 or 7q + 6
solve for q
7q + 3 =
7q + 3 -3 =-3
7q = -3
7q/7 = -3/7
q = -3/7
7q + 3 =
7q + 6 -6 =-6
7q = -6
7q/7 = -6/7
q = -6/7
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Answer:
here is your answer...
s=-3
<em /><em>10-s=? </em><u>Substitute s:</u>
10-(-3)=10+3=13
10-s=13
Answer: 13
Take the variable to be x
4x^3-7
