What are you asking? If it’s true or false it’s TRUE?
Step-by-step explanation:
Hi there!
The given equation is:
y = -2x + 5………………(i)
Comparing the equation with y = mx+c, we get;
m1 = -2
Also another equation of the line which passes through point (-4,2), we get;
(y-2) = m2(X+4)............(ii) { using the formula (y-y1) = m2(x-x2)}
According to the question, they are perpendicular to eachother, So according to the condition of perpendicular lines;
m1*m2 = -1
-2*m2 = -1
or, m2 = 1/2.
Therefore, m2= 1/2.
Now, keeping the value of m2 in equation (ii).
(y-2) = 1/2(x+4)
y = (1/2)x + 4
Therefore, the required equation is: y = (1/2)x + 4.
<u>Hope</u><u> it</u><u> helps</u><u>!</u>
The Answer is B.
Sol: (6/3x^(3-4))^2
= (2/x)^2
=4/x^2
Answer:
Step-by-step explanation:
hope that was the answer you were looking for :/
X=6 and x=1
You can find your zeros by determining what you have to plug into the function in order for it to equal zero
If we plug in 6, for example we’d get (6-6)(x-1)
Simplified this is 0(x-1)
Anything times 0 is 0, so this is one of our zeros.
Same goes for x-1, we just need to plug in 1 for it to equal 0
Therefore there are zeros at x=1 and x=6 :))
