No, that's not right. Sadly, the answer you entered on the
attached drawing is incorrect. It's slightly more complicated
than that ... only slightly.
First, think about this for a second: What if the two GIVEN angles
on the drawing had the same number of degrees ? Then by the
method you've been using, you would subtract them from each
other, and that would give you zero. So you would say that the
last angle is zero degrees ? Can you see that this doesn't really
work ?
Here's how it's really done:
It all rests on a rule about triangles. This is ALWAYS true, and
you should memorize it:
When you add up the degrees of all three angles
inside a triangle, the sum is ALWAYS 180 degrees.
So now, when you're given two of the angles, you know that
the unknown one must be exactly enough to bring the sum of
ALL of them up to 180 degrees.
Work it like this:
-- Take the two given angles.
-- ADD them.
-- Subtract their SUM from 180.
Now you have the third angle.
In the drawing you attached:
-- The given angles are 39 and 102 .
-- Add them: 39 + 102 = 141
-- Subtract the sum from 180: 180 - 141 = 39 .
The unknown angle is 39 degrees.
But that's the same as one of the given angles ! ? :-( ? :-(
That's OK. It's perfectly fine for two of the angles, or sometimes
even all three, to be the same size. They just have to all add up
to 180 degrees, and everything is fine.
Simply going to factorise this:
v(v - 1) -2(1 - v):
Note 1 - v = -(v-1)
<span>v(v - 1) -2(1 - v)
</span>
<span>v(v - 1) -2(-(v - 1))
</span>
<span>v(v - 1) +2(v - 1)</span>
(v + 2)(v - 1)
Given:
The vertices of the triangle are (-10,-3), (1,4) and (-1,7).
To find:
The perimeter of the triangle.
Solution:
Distance formula:
Let the vertices of the triangle are A(-10,-3), B(1,4) and C(-1,7).
Using distance formula, we get
Similarly,
Now, the perimeter of the triangle is
Therefore, the perimeter of the triangle is 30.098 units.
Answer:
The 2nd one
Step-by-step explanation:
Step-By-Step:
1. 3 times 10k=2 times 9
2. 3 times 10k=18
3. 3 times 10k/30 = 18/30
4. k=3/5 or 0.6
