Cos θ = adjacent / hypothenus = 5/13
opposite = sqrt(hypothenus^2 - adjacent^2) = sqrt(13^2 - 5^2) = sqrt(169 - 25) = sqrt(144) = 12
sec θ = 1/cos θ = 1/(adjacent / hypothenus) = hypothenus / adjacent = 13/5
cot θ = 1/tan θ = 1/(opposite/adjacent) = adjacent / opposite = 5/12
sec θ = 13/5
cot θ = 5/12
I don't see the problem on my screen try reposting it?
Answer:
d = 6.246 m
Step-by-step explanation:
Given that,
The distance around a circular pool is 39.25 m.
We need to find how does the lifeguard have to walk from the edge of the pool to the centre of the pool. It means we need to find the radius r of the circle.
ATQ,
Circumference = 2πr = 39.25 m
r is radius
So, the required distance is 6.246 m.
The figures that can have a triangle as a two-dimensional cross section are (4) I, III, and IV, only
<h3>How to determine the figures?</h3>
The cross-section of three-dimensional figures are as a result of slicing the figure along its axis.
- When the cube is sliced with its plane, it gives a triangle face
- When a cone is sliced vertically, it gives a triangle face
- One of the faces of a square pyramid is a triangle; so it has a triangle face
Hence, the figures that can have a triangle as a two-dimensional cross section are (4) I, III, and IV, only
Read more about cross section at:
brainly.com/question/3603397
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1+4(2x - 3)-x
Mutiply the bracket by 4
1+ (4)(2x)(4)(-3)-x
1+8x-12-x
8x-x+1-12 just rearranging
7x-11
Answer : D. 7x - 11
