All categories

3 years ago

Which of the following describes the graph of a linear function?

1 answer:

3 0

I believe that the last one is correct because it is not a curve but a straight line, and it can't be the second one because the y value does not decrease as x increases

You might be interested in

Please help. !!!!!!!!

Kryger [21]

Basically you find the data points and fill in the values. For Point J it is (2,4). They want you to do this: (2-4,4-6)...it then becomes (-2,-2).
So
J: (-2,-2)
K: (-1, -4)
I: (-2, -5)
Those are your new points. I hope this helps love! :)

8 0

3 years ago

Is it a function and whats the domain and range Picture below

marishachu [46]

No, because using the vertical line test, two points touch on the same line
[3, 3]
[3,4]

8 0

3 years ago

Which is the correct label of the line? (1 point) a AC O CD D Ο OllA

Scrat [10]

Answer:

The correct label of the line is CD

4 0

3 years ago

Can someone help me.. I’m about to cry- this stuff is due today

snow_tiger [21]

Answer:

For 5 - 10 it would be

-6a - 48

4 + 36x

-30n + 42

18m + 20

32 + 24n

-8b - 32

For numbers 1, 3, and 4

1. is b

2. is c

3. is d

4. a

5 0

3 years ago

Read 2 more answers

In order to set rates, an insurance company is trying to estimate the number of sick days that full time workers at an auto rep

son4ous [18]

Answer:

D. 31

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the population standard deviation is 2.8 days.

This means that $\sigma = 2.8$

How large a sample must be selected if the company wants to be 95% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

$M = z\frac{\sigma}{\sqrt{n}}$

$1 = 1.96\frac{2.8}{\sqrt{n}}$

$\sqrt{n} = 1.96*2.8$

$(\sqrt{n})^2 = (1.96*2.8)^2$

$n = 30.12$

Rounding up, at least 31 people are needed, and the correct answer is given by option D.

5 0

3 years ago