Ask question

Ask question

All categories

2 years ago

11

Two spoiled dogs eat a total of 18 treats in a certain amount of time. How many treats will 7 spoiled dogs eat during the same a

mount of time?
Please help :C

Will give 12 pts :D

1 answer:

rusak2 [61]2 years ago

6 0

Answer:

63 treats

Step-by-step explanation:

divide 18 by 2 and then multiply it by 7

18 / 2 = 9

9 * 7 = 63

I hope this helped :DDD

You might be interested in

yulyashka [42]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Hhiycycucucicuvuvuvu

suter [353]

Answer:

isjsuzizwjskzkzuziziss

6 0

2 years ago

Read 2 more answers

If a cross-country runner runs a 55 kilometer (km) race, how many miles is that? Round your answer to one decimal place.

prohojiy [21]

Answer: 34.2

For everyone 1 kilometer=.621371 so if you times that by 55 you get 34.1754 which rounds to 34.2

5 0

3 years ago

Please Help here, i really need this joe

NNADVOKAT [17]

Answer:

The first answer choice, 4632.5

Step-by-step explanation:

At the rate of 85 feet per hour, after 5.5 hours the apprentice would have covered 467.5 square feet. Subtracting this from the total amount of 5,100 square feet, you get 4632.5, or the first answer choice. Hope this helps!

5 0

3 years ago

Read 2 more answers

allsm [11]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

Let's solve!

Step-by-step explanation:

2x + 6x - 9 = 0

\____/

8x - 9 = 0

+ 9 + 9

<u>8x </u> = <u>9</u>

8 8

x = 9/8 --or-- $1\frac{1}{8}$

x = 1.125

I hope this helps!

6 0

3 years ago