Answer: Effect of outliers on mean median and mode
Outlier An extreme value in a set of data which is much higher or lower than the other numbers. Outliers affect the mean value of the data but have little effect on the median or mode of a given set of data.
Step-by-step explanation:
Answer:
Eddie O'Neil found a car advertised at a local used-car dealership for $34,000. The car is clean and in good condition. Its average retail value is $33,400.
Step-by-step explanation:
Answer:
p(w) - - - - - - p = 0.5w ; for 0 < w ≤ 8
p(w) - - - - - - p = 4 ; for w < 8 and w ≤ 12
Step-by-step explanation:
Price, p of weight of a toughurt serving :
p(w) - - - - - - p = 0.5w ; for 0 < w ≤ 8
p(w) - - - - - - p = 4 ; for w < 8 and w ≤ 12
Answer: three sets of value show 3 consecutive increases and they could be the intensities during fourth, fifth, and six visits:
- 66%, 69%, 72%;
- 63%, 65%, 67%, and
- 67%, 72%, 77%
Explanation:
1) The program recommends a constant intensity for 3 visits, which is what the table shows:
Day Intensisty
1 63%
2 equal ⇒ 63%
3 equal ⇒ 63%
2) Hence, you have to determine the valid sets that meet the recommendation for the fourth, fifth, and six visits, which are the next three.
2) For the next three visits, the program recommensd increasing intensities.
There are three options that show 3 consecutive increases; they are:
- 66%, 69%, 72%;
- 63%, 65%, 67%, and
- 67%, 72%, 77%
Therefore, those are the choices that apply.
Answer: 
.
Step-by-step explanation:
The given function is
Using chain rule differentiate w.r.t. x.
![\left[\because \dfrac{d}{dx}\sin x=\cos x\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Csin%20x%3D%5Ccos%20x%5Cright%5D)
![f'(x)=\cos(9\ln (x))\left[9\dfrac{d}{dx}(\ln (x))\right]](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Ccos%289%5Cln%20%28x%29%29%5Cleft%5B9%5Cdfrac%7Bd%7D%7Bdx%7D%28%5Cln%20%28x%29%29%5Cright%5D)
![f'(x)=\cos(9\ln (x))\left[9\times \dfrac{1}{x}\right]](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Ccos%289%5Cln%20%28x%29%29%5Cleft%5B9%5Ctimes%20%5Cdfrac%7B1%7D%7Bx%7D%5Cright%5D)
![\left[\because \dfrac{d}{dx}\ln x=\dfrac{1}{x}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Cln%20x%3D%5Cdfrac%7B1%7D%7Bx%7D%5Cright%5D)
Therefore, .
