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Alexxandr [17]
4 years ago
5

I dont get expresshions plz help me with these three questions asap

Mathematics
1 answer:
kifflom [539]4 years ago
5 0

Answer:

Step-by-step explanation:

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In a particular flow network G = (V,E) with integer edge capacities ce, we have already found the maximum s-t flow. However, we
yulyashka [42]

Answer:

Check the explanation

Step-by-step explanation:

1) Algorithm for finding the new optimal flux: 1. Let E' be the edges eh E for which f(e)>O, and let G = (V,E). Find in Gi a path Pi from s to u and a path P_1, from v to t.  

2) [Special case: If P_1, and P_2 have some edge e in common, then Piu[(u,v)}uPx has a directed cycle containing (u,v). In this instance, the flow along this cycle can be reduced by a single unit without any need to change the size of the overall flow. Return the resulting flow.]

3) Reduce flow by one unit along P_1U{(u,v)}UP_2

4) Run Ford-Fulkerson with this sterling flow.

Justification and running time: Say the original flow has see F. Lees ignore the special case (4 After step (3) Of the elgorithuk we have a legal flaw that satisfies the new capacity constraint and has see F-1. Step (4). FOrd-Fueerson, then gives us the optimal flow under the new cePacie co mint. However. we know this flow is at most F, end thus Ford-Fulkerson runs for just one iteration. Since each of the steps is linear, the total running time is linear, that is, O(lVl + lEl).

4 0
3 years ago
Find the measure of UT answer choice - 65 51 70 55​
muminat

Answer:

Option (4)

Step-by-step explanation:

If two chords intersect outside the circle, angle formed between the chords will be half of the sum of measures of intercepted arcs.

From the given picture,

m(\angle RQS)=\frac{1}{2}(m\hat{RS}+m\hat{UT})

95° = \frac{1}{2}(135+m\hat{UT})

190 = 135 + m(\hat{UT})

m(\hat{UT})=190-135

m(\hat{UT}) = 55°

Therefore, option (4) will be the correct option.

6 0
3 years ago
Someone please help me I need to help thank u I will give u 5 points
Yanka [14]

Answer:

I believe the answer is 14:)

6 0
3 years ago
Players in any sport who are having great​ seasons, turning in performances that are much better than anyone might have​anticipa
Sav [38]

Answer:

I pick the reasoning of option A

Step-by-step explanation:

I like the reasoning given in B, however, there are many cases of Athletes that, after reaching the top, maintain supremacy and improve over the years, adapting to their old age. Usually speed and physical resistance are replaced by technique and experience in the case of the top athletes.

I dont like C and D argument too much because being the best in a sport doesnt mean either that you reach the maximum level possible (in many cases you can keep growing) or that you dont have more motivations. Many athletes are super competitive people and they try to improve themselves all the time to reach, and stay, in the top.

I choose option A as answer because people on the cover doesnt neccesarily mean that they are the absolute best. Their performance was way better than their usual performance, and that may be due to either real skill growth, heavy training or a lucky streak. If it is a lucky streak, it is natural for that player's performance to go down into more terrenal levels for him. On the other hand, If he trained heavily, then he might have big injuries on later seasons and his performance wont be able to keep up for long. Thats why 'surprises' (that also sell better due to be a novelty) tend to go downhill after they reach the cover of sports illustrated.

7 0
4 years ago
In a fruit cocktail, for every 30 ml of orange juice you need 20 ml of apple juice and 50 ml of coconut milk. What proportion of
Orlov [11]

30+20+50 = 100 ml total. 20 ml is orange juice.

So, 30/100 reduce by dividing top and bottom by 30 gives

3/10 is the proportion of orange juice in the fruit cocktail.

Hope this helps! :)

7 0
2 years ago
Read 2 more answers
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