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Tems11 [23]
3 years ago
7

In a particular flow network G = (V,E) with integer edge capacities ce, we have already found the maximum s-t flow. However, we

made a mistake in the capacity values of edge (u, v): we used cuv but the capacity is only cuv − 1. Moreover, the max flow f uses edge (u, v) at full capacity. Can you find a new optimal flow faster than by recomputing max flow in G?
Mathematics
1 answer:
yulyashka [42]3 years ago
4 0

Answer:

Check the explanation

Step-by-step explanation:

1) Algorithm for finding the new optimal flux: 1. Let E' be the edges eh E for which f(e)>O, and let G = (V,E). Find in Gi a path Pi from s to u and a path P_1, from v to t.  

2) [Special case: If P_1, and P_2 have some edge e in common, then Piu[(u,v)}uPx has a directed cycle containing (u,v). In this instance, the flow along this cycle can be reduced by a single unit without any need to change the size of the overall flow. Return the resulting flow.]

3) Reduce flow by one unit along P_1U{(u,v)}UP_2

4) Run Ford-Fulkerson with this sterling flow.

Justification and running time: Say the original flow has see F. Lees ignore the special case (4 After step (3) Of the elgorithuk we have a legal flaw that satisfies the new capacity constraint and has see F-1. Step (4). FOrd-Fueerson, then gives us the optimal flow under the new cePacie co mint. However. we know this flow is at most F, end thus Ford-Fulkerson runs for just one iteration. Since each of the steps is linear, the total running time is linear, that is, O(lVl + lEl).

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Anni [7]

80 containers can be filled

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4 years ago
A building in a city has a rectangular base. The length of the base measures 75 ft less than three times the width. The
MariettaO [177]

The dimensions of the rectangular base of the building with the given perimeter are 120ft and 285ft.

<h3>What are the dimensions of the rectangle base?</h3>

The perimeter of rectangle is expressed as;

P = 2( l + w )

Given the data in the question;

Let x represent the width of the rectangular base.

  • Width w = x
  • Length = l = 3x-75
  • Perimeter P = 810ft

Plug these values into the equation above.

P = 2( l + w )

810 = 2( (3x-75) + x )

810 = 6x - 150 + 2x

810 = 8x - 150

8x = 810 + 150

8x = 960

x = 960/8

x = 120

Hence,

Width of the rectangle = x = 120ft

Length of the rectangle = 3x-75 = 3(120) - 75 = 285ft

Therefore, the dimensions of the rectangular base of the building with the given perimeter are 120ft and 285ft.

Learn more about rectangles here: brainly.com/question/17043956

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7 0
2 years ago
Factor by Grouping:<br> 8x²+12x+2xy+3y
Yuliya22 [10]

Answer:

(2x +3) (4x +y)

Step-by-step explanation:

refer the image

3 0
2 years ago
the population pf a city is 2,500. if the number of males is 240 more than the number of females how many males and females are
Masteriza [31]

You need to represent the number of males in terms of females.

Explanation:

Since you know the number of males relative to females, it makes sense to represent the number of females as a variable, let's say f.

So then the number of males is <span>f+240</span> and we know that the number of males plus the number of females is 2500. Knowing this, we can write an equation: <span>f+<span>(f+240)</span>=2500</span>. I put the number of males in brackets there just to make it easy to recognize.

This equation can be condensed into <span>2f+240=2500</span> and then solved:

<span>2f=2500−240</span>
<span>f=<span><span>2500−240</span>2</span></span>
<span>f=1130</span>

Then, we know the number of females, and we can solve for the number of males from here using our male formula: <span>males=f+240</span>. You should then get 1370 as the number of males.

Checking this answer, we see that 1130 + 1370 does equal 2500.


5 0
4 years ago
Write an equation in point slope form of a line that passes through the given point and has the given slope.
maxonik [38]

the equation of a line in point-slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = - 2 and (a, b) = (2, 6), hence

y - 6 = - 2(x - 2) ← equation in point-slope form


8 0
4 years ago
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