Answer:
C) 3(x + 3y + 5)
D) 3x + 3(3y +5)
-6x^2+4x
my reasoning:
eliminate the opposites (5 & -5)
collect the like terms (-8x^2 & + 2x^2)
collect the like terms again (-3x &+7x)
The point Q on a line segment with end points(2,1) and (4,2) is Q(12/5, -2/5)
<h3>What is a line segment?</h3>
A line segment is a straight line that passes through two given points.
The end points of the line determine how long or short a given line segment would be.
Analysis:
point Q(x, y )
x = 
y = 
where M :N = 4:1
x1 = 2, x2 = 4, y1 = -1, y2 = 2
x = 
= 12/5
y = 
= -2/5
In conclusion, the point Q is (12/5, -2/5).
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Because segments XY and XZ are of equal length, angle Y and angle Z must be congruent.
All inner angles must add to 180 degrees since it's a triangle.
70+70+x=180
140+x=180
x=40
Final answer: D
5. m∠C = 95°
6. m∠C = 70°
7. The other acute angle in the right triangle = 70°
8. m∠C = 70°
9. m∠C = 60° [equilateral triangle]
10. Measure of the exterior angle at ∠C = 110°
11. m∠B = 70°
12. m∠Z = 70°
<h3>What are Triangles?</h3>
A triangle is a 3-sided polygon with three sides and three angles. The sum of all its interior angles is 180 degrees. Some special triangles are:
- Isosceles triangle: has 2 equal base angles.
- Equilateral triangle: has three equal angles, each measuring 60 degrees.
- Right Triangle: Has one of its angles as 90 degrees, while the other two are acute angles.
5. m∠C = 180 - 50 - 35 [triangle sum theorem]
m∠C = 95°
6. m∠C = 180 - 25 - 85 [triangle sum theorem]
m∠C = 70°
7. The other acute angle in the right triangle = 180 - 90 - 25 [triangle sum theorem]
The other acute angle = 70°
8. m∠C = 180 - 55 - 55 [isosceles triangle]
m∠C = 70°
9. m∠C = 60° [equilateral triangle]
10. Measure of the exterior angle at ∠C = 50 + 60
Measure of the exterior angle at ∠C = 110°
11. m∠B = 115 - 45
m∠B = 70°
12. m∠Z = 180 - 35 - 75
m∠Z = 70°
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