Question

Write a C function namedliquid()that is to accept an integer number and theaddresses of the variablesgallons,quarts,pints, andcups. The passed integer rep-resents thetotalnumber of cups, and the function is to determine the number of gal-lons, quarts, pints, and cups in the passed value. Using the passed addresses, the functionshould directly alter the respective variables in the calling function. Use the relationshipsof 2 cups to a pint, 4 cups to a quart, and 16 cups to a gallon.

Answer 1

Answer:

#include <stdio.h>

#include <math.h>

void liquid(int ,int*,int*,int*,int*);

int main()

{

int num1, gallons, quarts, pints, cups;  

printf("Enter the number of cups:");

scanf("%2d",&num1);  

liquid(num1, &gallons, &quarts, &pints, &cups);  

return 0;

}  

void liquid(int x, int *gallons, int *quarts, int *pints, int *cups)

{

static int y;

y = x;  

if (y >= 16)

{

*gallons = (y / 16);

printf("The number of gallons is %3d\n", *gallons);

}

if (y - (*gallons * 16) >= 4)

{

*quarts = ((y - (*gallons * 16)) / 4);

printf("The number of quarts is %3d\n", *quarts);

}

if ((y - (*gallons * 16) - (*quarts * 4)) >= 2)

{

*pints = ((y - (*gallons * 16) - (*quarts * 4)) / 2);

printf("The number of pints is %3d\n", *pints);

}

if ((y - (*gallons * 16) - (*quarts * 4) - (*pints *2)) < 2 || y == 0)

{

*cups = (y - (*gallons * 16) - (*quarts * 4) - (*pints *2));

printf("The number of cups is %3d\n", *cups);

}

return;

}