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egoroff_w [7]
3 years ago
9

the points (3, 9) and (-3, -9) ate plotted on the coordinate plane using the equation y=a . x ... - did

Mathematics
1 answer:
slava [35]3 years ago
8 0

See the explanation

<h2>Explanation:</h2><h2></h2>

Here we have the following points:

(3,9) \ and \ (-3,-9)

The point-slope form of the equation of a line is:

y=ax+b \\ \\ \\ a:Slope \\ \\ b:y-intercept

So the slope can be found as:

a=\frac{-9-9}{-3-3} \\ \\ a=\frac{-18}{-6} \\ \\ a=3

So:

y=3x+b \\ \\ \\ Finding \ b: \\ \\ For \ x=3, \ y=9: \\ \\ \\ So: \\ \\ 9=3(3)+b \\ \\ b=9-9 \\ \\ b=0

So the equation is finally:

y=3x

This line passes through and is shown below.

<h2>Learn more:</h2>

About lines: brainly.com/question/14427236#

#LearnWithBrainly

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Can someone help please!
slava [35]

Answer: Area of the dotted line square is 120ft^2 and area of figure a. is 60 ft^2

Step-by-step explanation:

So the area of the dotted square/rectangle is 120 because we can take the entire length and width which is 10ft and 12 ft and multiply to find the area

Now the weird looking shape can be a little tricky but we have to remember that it is alot easier to solve for area of separate shapes. So if you look at the side of the 5ft and look all the way down we can see this figure makes both a rectangle and a triangle. The rectangle has a length of 10 and width of 4 so the area of that is 40ft^2. Now for the triangle. To find the base and height lengths 12-4 from the width of the rectangle which is 8 and 10-5 from height of the triangle so 5. Area of triangles is b*h/2 so 8*5/2= 20ft^2. So 40ft^2(rectangle)+20ft^2(triangle) is 60ft^2 area of figure a.

4 0
3 years ago
Solve each pair of simultaneous equations giving both solutions. You need to multiply both equations by suitable numbers before
Vladimir79 [104]

Answer:

a) x = 12  y = 9

b) x = -2   y = -4

c) x = 6   y = -2

Step-by-step explanation:

a)

Equation 1:  6x - 7y = 9

Equation 2:  3x + 2y = 54

Multiply Equation 2 by 2:

⇒ 6x + 4y = 108

Subtract equations:

   6x + 4y = 108

<u>-    6x - 7y = 9      </u>

           11y = 99

Divide both sides by 11:

⇒ y = 9

Substitute found value of y into Equation 1 and solve for x:

⇒ 6x - 7(9) = 9

⇒ 6x - 63 = 9

⇒ 6x = 72

⇒ x = 12

---------------------------------------------------------------------------------------------------

b)

Equation 1:  4x - 5y = 12

Equation 2:  2x - 3y = 8

Multiply Equation 2 by 2:

⇒ 4x - 6y = 16

Subtract equations:

   4x - 6y = 16

<u>-   4x - 5y = 12      </u>

           -y = 4

Divide both sides by -1:

⇒ y = -4

Substitute found value of y into Equation 1 and solve for x:

⇒ 4x - 5(-4) = 12

⇒ 4x + 20 = 12

⇒ 4x = -8

⇒ x = -2

---------------------------------------------------------------------------------------------------

c)

Equation 1:  4x - 2y = 28

Equation 2:  3x + 3y = 12

Multiply Equation 1 by 3:

⇒ 12x - 6y = 84

Multiply Equation 2 by 4:

⇒ 12x + 12y = 48

Subtract equations:

     12x - 6y = 84

<u>-   12x + 12y = 48   </u>

            -18y = 36

Divide both sides by -18:

⇒ y = -2

Substitute found value of y into Equation 1 and solve for x:

⇒ 4x - 2(-2) = 28

⇒ 4x + 4 = 28

⇒ 4x = 24

⇒ x = 6

6 0
2 years ago
Find the circumference of a circle that has a diameter of 4 m. Use 3.14 for pi. m
Arturiano [62]

Answer:

<h2>12.56 m</h2>

Step-by-step explanation:

The formula of a circumference of a circle:

C=d\pi

<em>d</em> - <em>diameter</em>

<em />

We have <em>d = 4m</em>.

Substitute:

C=4\pi\ m

Use 3.14 for π:

C\approx4(3.14)=12.56\ m

3 0
3 years ago
Which ordered pair can be removed so that the resulting graph represents a function?
Sunny_sXe [5.5K]

Answer:

(1, 3)

Step-by-step explanation:

6 0
2 years ago
Positive angles located in the fourth quadrant may be described as___.
gladu [14]

Answer:

Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360 .</u>

The option is

4. 270≤Ф≤360

Step-by-step explanation:

When the terminal arm of an angle starts from the x-axis in the anticlockwise direction then the angles are always positive angles.

For Example.

Quadrant I    - 0 to 90°

Quadrant II   - 90° to 180°

Quadrant III  - 180° to 270°

Quadrant IV - 270° to 360° ( 4. 270≤Ф≤360  )

Hence,Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360 .</u>

When the terminal arm of an angle starts from the x-axis in the clockwise direction than the angles are negative angles.

Quadrant IV  -          0° to -90°

Quadrant III   -      - 90° to -180°

Quadrant II    -      -180° to -270°

Quadrant I     -      -270° to -360°

5 0
3 years ago
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