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egoroff_w [7]
4 years ago
9

the points (3, 9) and (-3, -9) ate plotted on the coordinate plane using the equation y=a . x ... - did

Mathematics
1 answer:
slava [35]4 years ago
8 0

See the explanation

<h2>Explanation:</h2><h2></h2>

Here we have the following points:

(3,9) \ and \ (-3,-9)

The point-slope form of the equation of a line is:

y=ax+b \\ \\ \\ a:Slope \\ \\ b:y-intercept

So the slope can be found as:

a=\frac{-9-9}{-3-3} \\ \\ a=\frac{-18}{-6} \\ \\ a=3

So:

y=3x+b \\ \\ \\ Finding \ b: \\ \\ For \ x=3, \ y=9: \\ \\ \\ So: \\ \\ 9=3(3)+b \\ \\ b=9-9 \\ \\ b=0

So the equation is finally:

y=3x

This line passes through and is shown below.

<h2>Learn more:</h2>

About lines: brainly.com/question/14427236#

#LearnWithBrainly

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Given △ABC ∼ △LMN, find LNLN.
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Well in order to find the equation you are looking for you first must find the slope of the line.  Since it gives you two points at (-4, 1) and at (0, 4), use these points to find the slope.  

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The Institute of Education Sciences measures the high school dropout rate as the percentage of 16- through 24-year-olds who are
STALIN [3.7K]

Answer:

We conclude that the proportion of dropouts has changed from the historical value of 0.081.

Step-by-step explanation:

We are given that in 2009, the high school dropout rate was 8.1%. A polling company recently took a survey of 1000 people between the ages of 16 and 24 and found 6.5% of them are high school dropouts.

The polling company would like to determine whether the proportion of dropouts has changed from the historical value of 0.081.

<em>Let p = proportion of school dropouts rate</em>

SO, <u>Null Hypothesis,</u> H_0 : p = 0.081   {means that the proportion of dropouts has not changed from the historical value of 0.081}

<u>Alternate Hypothesis</u>, H_A : p \neq 0.081   {means that the proportion of dropouts has changed from the historical value of 0.081}

The test statistics that will be used here is <u>One-sample z proportion statistics</u>;

             T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p  = sample proportion of high school dropout rate = 6.5%

            n = sample of people = 1000

So, <u><em>test statistics</em></u>  =   \frac{0.065-0.081}{{\sqrt{\frac{0.065(1-0.065)}{1000} } } } } 

                               =  -2.05

<u>Also, P-value is given by the following formula;</u>

         P-value = P(Z < -2.05) = 1 - P(Z \leq 2.05)

                                              = 1 - 0.97982 = <u>0.0202</u> or 2.02%

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Therefore, we conclude that the proportion of dropouts has changed from the historical value of 0.081.

7 0
3 years ago
(3c^2 −5cd+d^2 )−(7c^2 +4cd−9d^2 )
valentina_108 [34]

(3c^2 − 5cd + d^2) − (7c^2 + 4cd − 9d^2) =

1. Drop the parentheses around the first polynomial since they are not needed.

= 3c^2 − 5cd + d^2 − (7c^2 + 4cd − 9d^2)

2. To drop the parentheses around the second polynomial, every sign inside changes.

= 3c^2 − 5cd + d^2 − 7c^2 - 4cd + 9d^2

3. Combine like terms. Like terms have the same variables and exponents.

= 3c^2 - 7c^2 - 5cd - 4cd + d^2 + 9d^2

= -4c^2 - 9cd + 10d^2

5 0
3 years ago
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