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Simora [160]
3 years ago
9

Please help me I hate math

Mathematics
2 answers:
Sladkaya [172]3 years ago
8 0
To classify this triangle, we need to look at it's angles, and know the definition of each of the triangles. We know that the triangle will have to be either right, obtuse, or acute. An obtuse triangle has one angle that is greater than or equal to 120°, a right triangle has an angle that is equal to 90°, and an acute triangle has all three angles less than 90°. Since this triangle has all its angles less than 90°, it is an acute triangle, or B.
podryga [215]3 years ago
3 0
The triangle classifies as a acute triangle.
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Someone answerrrrrr plssss ASAP!!!!!!’
ikadub [295]

Answer:

9. It seems he was inactive/taking a break, as the line is completely straight.

I'm not sure about the others, but I hope that helps!

Step-by-step explanation:

4 0
2 years ago
Enter the explicit rule for the sequence
Softa [21]
Let's take a look at the first few numbers in the sequence based on the given rule:

a_{1}=6\\ a_{2}= \frac{1}{4}(6)\\ a_3= \frac{1}{4}\big( \frac{1}{4}\big)6= \big(\frac{1}{4}\big)^2(6)\\ a_{4}= \frac{1}{4} \big(\frac{1}{4}\big)^26= \big(\frac{1}{4}\big)^3(6)

Inspecting this pattern it seems like the power \frac{1}{4} is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be \big(\frac{1}{4} \big)^{n-1}. We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as

a_n=6\big( \frac{1}{4} \big)^{n-1}

Where a_n is the nth number in our sequence.
8 0
3 years ago
Please I need help ASAP, please tell me how you know
mixas84 [53]

Answer: D it the For the way they have as examples

what do you need help on. what the problem

7 0
2 years ago
The sum of the digits of a two-digit number is 13. Twice the first digit is 1 less than the second digit. What is the two digit
Alex

Answer:

6 and 7

Step-by-step explanation:

10(13-X) + X= 13-9X. 3×2=6. 7-6=1. 7+6=13

4 0
3 years ago
For a standard normal random variable, what z-score has (a) probability 0.175 to the right?
Mumz [18]
Answer: 0.935

Explanation: 

Let S = z-score that has a probability of 0.175 to the right. 

In terms of normal distribution, the expression "probability to the right" means the probability of having a z-score of more than a particular z-score, which is Z in our definition of variable Z. In terms of equation:

P(z ≥ S) = 0.175   (1)

Equation (1) is solvable using a normal distribution calculator (like the online calculator in this link: http://stattrek.com/online-calculator/normal.aspx). However, the calculator of this type most likely provides the value of P(z ≤ Z), the probability to the left of S.

Nevertheless, we can use the following equation:

P(z ≤ S) + P(z ≥ S) = 1 
⇔ P(z ≤ S) = 1 - P(z ≥ S)  (2)

Now using equations (1) and (2):

P(z ≤ S) = 1 - P(z ≥ S)
P(z ≤ S) = 1 - 0.175 
P(z ≤ S) = 0.825

Using a normal distribution calculator (like in this link: http://stattrek.com/online-calculator/normal.aspx),

P(z ≤ S) = 0.825
⇔ S = 0.935 

Hence, the z-score of 0.935 has a probability 0.175 to the right.
7 0
3 years ago
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