50:40=x:35
5/4=x/35
times both sides by (4*35)
5*35=4x
175=4x
divide both sides by 4
43.75=x
costs $43.75
Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
The total of 2 buckets of popcorn and 3 boxes of candy would be $23.25
To answer this question you need to form a set of simultaneous equations and solve them. We can do this by saying that a bucket of popcorn = P, and a box of candy = C. Then we can say:
4P + 6C = 46.50
P + C = 9.75
There are then two possible ways to solve; you can either say that C = 9.75 - P using the second equation and then substitute it into the first, or you can multiply the second equation by either 4 or 6 to cancel out P or C.
I’m going to multiply the second equation by 4:
4P + 4C = 39
Now we can subtract this for, the first equation:
4P + 6C = 46.50
4P + 4C = 39
2C = 7.50
C = 3.75
Now we can substitute this value of C into one of the equations to find P:
P + C = 9.75
P + 3.75 = 9.75
P = 6
And now to answer the question, you just multiply P by 2 and C by 3 and add them together, which gives you $23.25
I hope this helps! Let me know if you have any questions :)
9
27/9 = 3
54/9 = 6
81/9 = 9
