Answer:
Maureen earned $123.19 doing odd jobs
Step-by-step explanation:
The compound interest formula is given by:

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit year and t is the time in years for which the money is invested or borrowed.
In this question:
Compounded quarterly means that 
10 years, so 
9% interest, so 
There is $300.00 in the account, which means that 
How much did Maureen earn doing odd jobs?
This is P.





Maureen earned $123.19 doing odd jobs
Answer: A and C
Explanation: 6766 x 1/4 = 1,691.5, 6766 x 1/2 = 3383
Hope this helps
Answer:
Part A: Two pieces of information that are provided by the graph is the median which is 55 and the range which is 20-95. Two piece of information that is not provided by the graph is the mean and mode.
Part B: The interquartile range of the data is 25. It represent the range between the amount of time in minutes that the students of a class surfed the internet.
I am not sure if this is all correct, but i tired. I hope this helps :)
Answer:
the cost that used to frame the math certificate is $847.80
Step-by-step explanation:
The computation of the cost that used to frame the math certificate is shown below:
= 27 wide × 20 tall × $1.57 per centimeter
= $847.80
Hence, the cost that used to frame the math certificate is $847.80
Answer:
See explanation
Step-by-step explanation:
Factorize numbers 42 and 56:

These two numbers have common factors 2 and 7. So,
A. Mr. Ellis can divide the group into
- 1 team = 42 ten-year-olds and 56 nine-year-olds (actually this is not dividing only completing 1 team);
- 2 teams = 21 ten=year-olds and 28 nine-year-olds in each team;
- 7 teams = 6 ten-year-olds and 8 nine-year-olds in each team;
- 14 teams = 3 ten-year-olds and 4 nine-year-olds in each team.
So, there are 3 different ways to divide the group of students into teams.
B. The greatest number of teams Mr. Ellis can make so each team has the same number of 9-year-olds and the same number of 10-year-olds is 14 teams.
C. If Mr. Ellis gives a snack to each winner, then he is interested to give the smallest number of snacks, the smallest number of snacks will be when the number of students in the team is the smallest, the smallest number of students will be when the greatest number of teams are created.