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dangina [55]
3 years ago
15

Find the value of x. correct answer please

Mathematics
1 answer:
liq [111]3 years ago
5 0

Answer:

x =  \sqrt{30}

Step-by-step explanation:

By Geometric mean property:

BD =  \sqrt{3 \times 7}  \\ BD =  \sqrt{21} \\ by \: pythagoras \: theorem \\  {x}^{2}  =  { (\sqrt{21}) }^{2}  +  {(3)}^{2}  \\  {x}^{2}  = 21 + 9 \\  {x}^{2}  = 30 \\ x =  \sqrt{30}

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Random selection refers to
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Use the graph to write the factorization of x^2+2x-8
kozerog [31]

Answer:

(x-2)(x+4)

Step-by-step explanation:

So it would be A.

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8 0
3 years ago
Read 2 more answers
A cylindrical base has a diameter of 6 inches. At the bottom of the vase, there are 9 marbles, each of the diameter 3 inches. Th
alexandr1967 [171]

Answer:

\sf C. \quad \pi (3\:in)^2(12\:in)-9 \left(\dfrac{4}{3} \pi (1.5\:in)^3 \right)

Step-by-step explanation:

To find the volume of water in the vase, subtract the volume of the marbles from the volume of the cylindrical vase.

..............................................................................................................................

The marbles can be modeled as <u>spheres</u>.

<u>Volume of a sphere</u>

\sf V=\dfrac{4}{3}\pi r^3 \quad \textsf{(where r is the radius)}

<u>Radius</u>

\sf r = \dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

Therefore, the volume of 9 marbles, each of diameter 3 inches is:

\sf Volume & = \sf 9 \left(\dfrac{4}{3} \pi (1.5\:in)^3 \right)

..............................................................................................................................

The vase can be modeled as a <u>cylinder</u>.

<u>Volume of a cylinder</u>

\sf V=\pi r^2 h \quad \textsf{(where r is the radius and h is the height)}

Therefore, the volume of a cylinder with a base of diameter 6 in and a height of 12 in is:

\sf Volume =\pi (3\:in)^2(12\:in)

..............................................................................................................................

<u>Volume of water</u>

<u />

\begin{aligned}\implies \sf Volume\:of\:water & = \sf Volume\:of\:vase- Volume\:of\:marbles\\& = \sf \pi (3\:in)^2(12\:in)-9 \left(\dfrac{4}{3} \pi (1.5\:in)^3 \right)\end{aligned}

8 0
2 years ago
How can the sum be found using mental math?
leonid [27]

Answer:233

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6 0
3 years ago
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