If a polynomial has one root in the form a+√b , it has a second root in the form of a_√b

Mathematics

1 answer:

Elina [12.6K]2 years ago

3 0

Answer:

Step-by-step explanation:

a+√b

a-√b

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3. If triangle ABC has the following measurements, find the measure of angle A.

klio [65]

9514 1404 393

Answer:

(a) 42.3°

Step-by-step explanation:

Side 'a' is the shortest of three unequal sides, so angle A will be the smallest angle in the triangle. Its measure can be found from the Law of Cosines.

a² = b² +c² -2bc·cos(A)

cos(A) = (b² +c² -a²)/(2bc) = (21² +25² -17²)/(2·21·25) = 777/1050

A = arccos(777/1050) ≈ 42.3°

The measure of angle A is about 42.3°.

_____

Additional comment

The smallest angle in a triangle can never be greater than 60°. This lets you eliminate choices that exceed that value.

5 0

2 years ago

If two points known on the line AB in the coordinate plane is (7,15) and (18,42), calculate the following..

Ksju [112]

Answer:

Slope = 27/11
AB = 29.15 u

Step-by-step explanation:

Given :-

Two points are given to us .
The points are A(7,15) and B(18,42)

To Find :-

The slope of the line .
The length of line AB .

We can find the slope of the line passing through the points $( x_1,y_1)$ and $( x_2,y_2)$ as ,

$\implies m = \dfrac{ y_2-y_1}{x_2-x_{1}}$

Plug in the respective values ,

$\implies m = \dfrac{ 42-15}{18-7} \\\\\implies \boxed{ m = \dfrac{ 27}{11 }}$

Hence the slope of the line is 27/11 .

$\rule{200}2$

Finding the length of AB :-

We can find the distance between them by using the Distance Formula .

$\implies Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2} \\\\\implies Distance =\sqrt{ (18-7)^2+(42-15)^2 } \\\\\implies Distance =\sqrt{ 11^2 + 27^2 } \\\\\implies Distance =\sqrt{ 121 + 729 } \\\\\implies Distance = \sqrt{ 850} \\\\\implies \boxed{ Distance = 29.15 \ units }$