Answer: this question is incomplete
Step-by-step explanation:
X = -3.
The distance from p(-9, 0, 0) is
d = sqrt((x+9)^2 + y^2 + z^2)
The distance from q(3,0,0) is
d = sqrt((x-3)^2 + y^2 + z^2)
Let's set them equal to each other.
sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
Square both sides, then simplify
(x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
18x + 81 = - 6x + 9
24x + 81 = 9
24x = -72
x = -3
So the desired equation is x = -3 which defines a plane.
Answer:16b square root of 5 -8
Step-by-step explanation:
Answer:
B is the correct answer
Kevin is K
Daniel is D
Now: K
K = D + 3
3 years ago:
K - 2 = 4(d - 2)
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Answer:
x = -5
Step-by-step explanation:
1. Divide both sides by -3
2. Simplify 15/-3 to 5
( 15 divided by -3 is -5)
