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3 years ago

Please help me anybody

Mathematics

2 answers:

Zina [86]3 years ago

8 0

Answer:

3/2

Step-by-step explanation:

Use the rise over run method, 3 squares up from the first point and 2 to the right gets you to the second point so it is 3/2.

Viefleur [7K]3 years ago

3 0

Answer:

Step-by-step explanation:

3 up, 2 to the side

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Please help me answer this equation

krok68 [10]

Answer:

Step-by-step explanation:

What you do is try to find l by using the given information.

We can start by saying that

A=L*W

Now it's easy algebra

Divide both sides by W

L=A/W

Area and length are given .

A=((m^3-3m+2)/2m^2-7m+3)/(m^3+m-2)/(2m^3+3m-2)

Try to work it out if you can't then tell me in the comments we'll figure it out.

4 0

3 years ago

In words how do you write 1000

valkas [14]

Easy... :)

1,000= One thousand.

Thus, your answer. :D

8 0

4 years ago

Read 2 more answers

How to solve 5-(49/1-5)x2+9-3

prisoha [69]

Final result : -77

Step by step solution :

Step 1 :

Simplify ——

Equation at the end of step 1 :

((5 - ((49 - 5) • 2)) + 9) - 3

Step 2 :

Final result :

-77

Hope this helps!

5 0

3 years ago

Read 2 more answers

Lucas and William are playing a video game and they have scored a total of 20,000 points. Lucas scored 1000 more than Williams.

const2013 [10]

Answer:

Hey there!

The system can be written as

l+w=20000

w+1000=l

Let me know if this helps :)

8 0

3 years ago

Two perpendicular lines have opposite y-intercepts. The equation of one of these lines is

xeze [42]

Answer: The required x-co-ordinate of the point of intersection of two lines is $-\dfrac{2bm}{m^2+1}.$

Step-by-step explanation: Given that two perpendicular lines have opposite y-intercept and the equation of one of the lines is

$y=mx+b.$

We are to express the x-coordinate of the intersection point of the lines in terms of m and b.

Let the slope and y-intercept of the other line be s and c respectively.

Since the product of the slopes of two perpendicular lines is -1 and -b is the opposite of b, so we have

$ms=-1~~~\Rightarrow s=-\dfrac{1}{m}$

and c = -b.

That is, the equation of the other line is

$y=sx+c\\\\\Rightarrow y=-\dfrac{1}{m}-b.$

Comparing the equations of both the lines, we get

$mx+b=-\dfrac{1}{m}x-b\\\\\\\Rightarrow mx+\dfrac{1}{m}x=-2b\\\\\\\Rightarrow \dfrac{m^2+1}{m}x=-2b\\\\\\\Rightarrow x=-\dfrac{2bm}{m^2+1}.$

Thus, the required x-co-ordinate of the point of intersection of two lines is $-\dfrac{2bm}{m^2+1}.$

3 0

4 years ago