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olga nikolaevna [1]
3 years ago
9

From your first quiz to your second quiz the score dropped eight points the score on the second quiz was 39. What was the first

quiz score?
Mathematics
2 answers:
marissa [1.9K]3 years ago
8 0

Answer:

47

Step-by-step explanation:

Let the score of your first quiz be "x"


x-8=39

39+8=47

Maslowich3 years ago
4 0
The first quiz score was 39 + 8 = 47.
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AACB = ADCE <br>&lt;A=50°, &lt;C=45°, and &lt;D=10x <br>x=[?]​
motikmotik

Answer:

X=5

Step-by-step explanation:

Angle A is congruent to angle D.

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2.4 + 5.4q – 4.5q + 3.6<br><br> a.6+1.1q<br> b.9.9q+6<br> c.0.9q+6<br> d.9.9q-6
Yuri [45]
You have to add the same kind of terms, in this case the ones that have a variable (5.4q and -4.5q) and the ones that don't (2.4 and 3.6), like this:

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The answer is c. 0.9 +6

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3 years ago
Use the sample information 11formula13.mml = 37, σ = 5, n = 15 to calculate the following confidence intervals for μ assuming th
bija089 [108]

Answer & Step-by-step explanation:

The confidence interval formula is:

I (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]

alpha= is the proposition of the distribution tails that are outside the confidence interval. In this case, 10% because 100-90%

σ= standard deviation. In this case 5

mean= 37

n= number of observations. In this case, 15

(a)

Z(alpha/2)= is the critical value of the standardized normal distribution. The critical valu for z(5%) is 1.645

Then, the confidence interval (90%):

I 90%(μ)= 37+- [1.645*(5/sqrt(15))]

I 90%(μ)= 37+- [2.1236]

I 90%(μ)= [37-2.1236;37+2.1236]

I 90%(μ)= [34.8764;39.1236]

(b)

Z(alpha/2)= Z(2.5%)= 1.96

Then, the confidence interval (90%):

I 95%(μ)= 37+- [1.96*(5/sqrt(15)) ]

I 95%(μ)= 37+- [2.5303]

I 95%(μ)= [37-2.5303;37+2.5303]

I 95%(μ)= [34.4697;39.5203]

(c)

Z(alpha/2)= Z(0.5%)= 2.5758

Then, the confidence interval (90%):

I 99%(μ)= 37+- [2.5758*(5/sqrt(15))

I 99%(μ)= 37+- [3.3253]

I 99%(μ)= [37-3.3253;37+3.3253]

I 99%(μ)= [33.6747;39.3253]

(d)

C. The interval gets wider as the confidence level increases.

8 0
3 years ago
Calculamos el volumen (V) de un prisma cuadrangular expresado en unidades cúbicas. Respondemos: ¿cómo se calcula?...............
Vadim26 [7]

Answer:

a) El procedimiento queda resumido en lo que sigue:

1) Se halla el área de la base del cuadrilátero.

2) Se multiplica el resultado anterior por la longitud del prisma.

b) La expresión para calcular el volumen del prisma (V), en unidades cúbicas, es:

V = w\cdot h \cdot l

Donde:

w - Ancho de la base, en unidades.

h - Altura de la base, en unidades.

l - Longitud del prisma, en unidades.

Step-by-step explanation:

a) Dimensionalmente hablando, la unidad de volumen es igual al cubo de la unidad de longitud. Se explica a continuación los pasos necesarios para el cálculo de prisma cuadrangular:

1) Se halla el área de la base del cuadrilátero.

2) Se multiplica el resultado anterior por la longitud del prisma.

b) En consecuencia, se deriva la expresión para el volumen del prisma:

V = A\cdot l (1)

Donde:

A - Área de la base del prisma, en unidades cuadradas.

l - Longitud del prisma, en unidades.

V = w\cdot h \cdot l (2)

Donde:

w - Ancho de la base, en unidades.

h - Altura de la base, en unidades.

5 0
3 years ago
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