domain is 10 and range is 5 and another domain is 10 and range is -3
If the amount she saved was $6 for 20%, then the formula for finding savings would be cost*percentage.
But if you want to find the original cost, then you play with the current formula until you get this. $6/20%. Have a good one :)
Answer:
84.38% probability that he succeeds on at least two of them
Step-by-step explanation:
For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
He has a 3/4 probability of success.
This means that 
Giannis shoots three free throws
This means that 
What is the probability that he succeeds on at least two of them





84.38% probability that he succeeds on at least two of them
The 1st choice is the correct one.
Isabel is correct because the y-intercept of Line B is (0, 9) and the value of y when x = 0 in Parabola A is 9.
Answer:
First, Second and Last Options are correct choices.
Step-by-step explanation:
Regards: Umer