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elixir [45]
3 years ago
14

Isabella uses one-foot cubical blocks to build a rectangular fort that is 12 feet long, 10 feet wide, and 5 feet high. The floor

and the four walls are all one foot thick. How many blocks does the fort contain?

Mathematics
1 answer:
jonny [76]3 years ago
5 0

Answer:

12

trust me it works i just took the test.

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The main sail of a sailboat has the dimensions shown in the figure at the right. What is the height of the main sail?
levacccp [35]

Answer:

h = 16.1

Step-by-step explanation:

sin A /a = sin B / b = sin C/c   where A is angle and a is side opposite of angle

sin (49) / h = sin(41)/ 14       cross-multiply

h*sin(41) = 14 * sin(49)

h = (14*sin(49))/ sin(41)

h = 16.1

5 0
2 years ago
What is 1,200,354,226,320 divided by 666,222,346
aleksklad [387]

1,200,354,226,320 divided by 666,222,346 is 1801.73216

6 0
3 years ago
Read 2 more answers
Line segment JK measures 17cm. Segments JK was translated 4 units right and 8 units up for for J'K'. What is the measurement of
castortr0y [4]

Answer:

c

Step-by-step explanation:

8 0
2 years ago
The sum of the measures of the angles of a triangle is 180°. The middle-sized angle measures 3° more than 2 times the smallest a
Anit [1.1K]

Answer:

13° , 29° , 138°

Step-by-step explanation:

let x be the smallest angle , then

2x + 3 is the middle angle and

2x + 3 + 109 is the largest angle

summing the 3 angles and equating to 180

x + 2x + 3 + 2x + 3 + 109 = 180 , that is

5x + 115 = 180 ( subtract 115 from 180 )

5x = 65 ( divide both sides by 5

x = 13

2x + 3 = 2(13) + 3 = 26 + 3 = 29

2x + 3 + 109 = 29 + 109 = 138

the 3 angles are 13° , 29° , 138°

6 0
2 years ago
Jared has a wooden board that is 11 ft long. He wants to cut it into 2 pieces so that the longer piece is 4 ft less than 4 times
Kaylis [27]
X+y=11

x is longer than y
x>y
x is 4 less than 4 times y
x=-4+4y

sub back
x+y=11
-4+4y+y=11
-4+5y=11
add 4 to both sides
5y=15
divide both sides by 5
y=3

sub back
x=-4+4y
x=-4+4(3)
x=-4+12
x=8

the pieces are 8ft and 3ft
4 0
3 years ago
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