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3 years ago

14

Isabella uses one-foot cubical blocks to build a rectangular fort that is 12 feet long, 10 feet wide, and 5 feet high. The floor

and the four walls are all one foot thick. How many blocks does the fort contain?

1 answer:

jonny [76]3 years ago

5 0

Answer:

12

trust me it works i just took the test.

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DONE ASAP PLZ!!!! If the volume of a sphere is represented by the equation V= 4/3πr³. Solve for r. Show work to receive 25 point

den301095 [7]

Answer:

∛V / (4/3π) = r

Step-by-step explanation:

V = 4/3πr³

Try to isolate r if you want to solve for it.

So divide everything that's not r from the right side in order to move it to the left side of the equation.

V / (4/3π) = r³

Then since it is raised to the power of 3 , just cube root the other side in order to undo the exponent. This is so you can isolate r.

∛(V/(4/3π)) = r

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3 years ago

Sequence of numbers 1.5,2.25,3.0,3.75 in a recursive formula?

stellarik [79]

Answer:

f(n + 1) = f(n) + 0.75

Step-by-step explanation:

7 0

3 years ago

87628 divided by 931

Svetlanka [38]

94.1224489795918367 is the answer to your question

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3 years ago

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As accounts manager in your company, you classify 75% of your customers as "good credit" and the rest as "risky credit" dependin

Elena-2011 [213]

Answer:

The percentage of overdue accounts are held by customers in the "risky credit" category is 62.5%

Step-by-step explanation:

Customers in the "risky" category (25% of total accounts) allow their accounts to go overdue 50% of the time on average.

That means that on average, 12.5% of total accounts is overdue.

0.25*0.50 = 0.125

In the "good credit" category only 10% goes overdue. That means 7,5% of total accounts goes overdue in this category.

0.75*0.10=0.075

The total accounts that go overdue is 0.125+0.075 = 0.200.

The percentage of overdue accounts held by customers in the "risky credit" category is:

0.125/0.200 = 0.625 or 62.5%

4 0

3 years ago

Consider independent simple random samples that are taken to test the difference between the means of two populations. The varia

Arturiano [62]

Answer:

d. t distribution with df = 80

Step-by-step explanation:

Assuming this problem:

Consider independent simple random samples that are taken to test the difference between the means of two populations. The variances of the populations are unknown, but are assumed to be equal. The sample sizes of each population are n1 = 37 and n2 = 45. The appropriate distribution to use is the:

a. t distribution with df = 82.

b. t distribution with df = 81.

c. t distribution with df = 41.

d. t distribution with df = 80

Solution to the problem

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

This last one is an unbiased estimator of the common variance $\sigma^2$

So on this case the degrees of freedom are given by:

$df= 37+45-2=80$

And the best answer is:

d. t distribution with df = 80

5 0

3 years ago