Question

Find the equation of the line through (- 7, - 2) that is perpendicular to the line y = x/3 + 6 .

Answer 1

Answer:

y+3x+23=0

Step-by-step explanation:

From y = x/3 + 6 comparing with general equation of a line, y = mx +c

m1 = 1/3

Perpendicularity rule states that m1m2 = -1

m2 = -1/1/3 = -1 * 3/1 = -3

The equation is

y-y1 = m2(x-x1)

y-(-2) = -3(x-(-7))

y+2 = -3(x+7)

y+2 = -3x-21

y = -3x-21-2

y= -3x-23

y+3x = -23

y+3x+23=0