we are given that
f(x) is defined for all values of x except at x=c
Limit may or may not exist
case-1:
If there is hole at x=c , then limit exist
case-2:
If there is vertical asymptote at x=c , then limit does not exist
Examples:
case-1:

We can simplify it



so, we can see that limit exist and it's value defined
case-2:

Left limit is


Right Limit is


so, we can see that left limit is not equal to right limit
so, limit does not exist
Kate's situation is correct because she put 2 muffins each in 7 boxes, which is saying 7 x 2. If you multiply these factors together, you will get 14 muffins; which is the amount that Kate started with.
Answer:
y - 3 = 6(x + 8)
Step-by-step explanation:
The point-slope form of the equation of a line with slope m through point (h, k) is ...
y -k = m(x -h)
When you fill in the given values, you get ...
y -3 = 6(x -(-8))
and that simplifies to
y -3 = 6(x +8)
Answer:
A) <RXZ and <YXZ
Step-by-step explanation:
I just took the test