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charle [14.2K]
3 years ago
12

What is the 8th term in the sequence? an=25−3n

Mathematics
1 answer:
Andru [333]3 years ago
8 0

Answer:

<h2>a₈ = 1</h2>

Step-by-step explanation:

\text{Put}\ n=8\ \text{to the sequence}\ a_n=25-3n:\\\\a_8=25-3(8)=25-24=1

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What is the slope of any line that is perpendicular to the line that contains the points (8,8) and (12,12)
svetlana [45]

Answer: 1

Step-by-step explanation:

12-8=4

12-8=4

4 over 4 is 1

if it perpendicular then it's the opposite reciprocal

hope that help

8 0
2 years ago
The area of a right triangle is 16 square
statuscvo [17]

Answer:

Well if it volume it would be 16 × 2 which is 32 then that would 32 × 16=512

but you wrote area so it would be 16

6 0
3 years ago
Which point is a solution to the inequality shown in this graph?
kykrilka [37]

Answer:

The only solution can be (0,-3) point.

Step-by-step explanation:

We have to judge whether the points in options are the solution to the graphed inequality or not.

The first point is (5,-5) which not included in the shaded region of the graph. Hence, it can not be a solution.

The second point is (6,0) which not included in the shaded region of the graph. Hence, it can not be a solution.

The third point is (0,-5) which not included in the shaded region of the graph. Hence, it can not be a solution.

The fourth point is (0,-3). It is on the firm red line which is included in the shaded region of the graph. Hence, it is a solution.

Therefore, the only solution can be (0,-3) point. (Answer)

5 0
3 years ago
Bill has lost 40<br>pounds in 8<br>weeks. What is<br>his weekly rate?​
choli [55]

Answer:

5 pounds

Step-by-step explanation:

40 divided by 8 = 5

6 0
3 years ago
Read 2 more answers
how many such tests would it take for the probability of committing at least one type i error to be at least 0.7? (round your an
drek231 [11]

The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118   .

In the question ,

it is given that ,

the probability of committing at least , type I error is = 0.7

we  have to find the number of tests ,

let the number of test be n ,

the above mentioned situation can be written as

1 - P(no type I error is committed) ≥ P(at least type I error is committed)

which is written as ,

1 - (1 - 0.01)ⁿ ≥ 0.7

-(0.99)ⁿ ≥ 0.7 - 1

(0.99)ⁿ ≤ 0.3

On further simplification ,

we get ,

n ≈ 118 .

Therefore , the number of tests are 118 .

Learn more about Error here

brainly.com/question/17062640

#SPJ4

4 0
1 year ago
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