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3 years ago

What is the 8th term in the sequence? an=25−3n

Mathematics

1 answer:

Andru [333]3 years ago

8 0

Answer:

Step-by-step explanation:

$\text{Put}\ n=8\ \text{to the sequence}\ a_n=25-3n:\\\\a_8=25-3(8)=25-24=1$

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Diameter of a circle is two units. What is the radius of the circle?

bonufazy [111]

Answer is 3.5 feet enjoy

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2 years ago

The first eight quizzes in this class had average scores of 8,9,9,8,8,9,8,7. This gives a sample mean of 8.25 and a sample stand

alexira [117]

Answer:

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

t = 1.076

Step-by-step explanation:

Step(i):-

Given Mean of the Population (μ) = 8.0

Mean of the sample (x⁻) = 8.25

Given data

8,9,9,8,8,9,8,7

Given sample size n= 8

Given sample standard deviation(S) = 0.661

Step(ii):-

Null hypothesis : H: (μ) = 8.0

Alternative Hypothesis :H:(μ) > 8.0

Degrees of freedom = n-1 = 8-1=7

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

$t = \frac{8.25 -8.0}{\frac{0.661}{\sqrt{8} } }$

t = 1.076

Critical value

t₍₇,₀.₀₅₎ = 2.3646

The calculated value t = 1.076 < 2.3646 at 0.05 level of significance

Null hypothesis is accepted

Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0

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3 years ago

(6x-9)+5=2 can you solve this

ehidna [41]

(6x -9) + 5= 2
= -54 + 5
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2 years ago

Read 2 more answers

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

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3 years ago

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vovangra [49]

Answer: Your answer is 50

Step-by-step explanation:

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2 years ago