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4 years ago

What is the 8th term in the sequence? an=25−3n

Mathematics

1 answer:

Andru [333]4 years ago

8 0

Answer:

Step-by-step explanation:

$\text{Put}\ n=8\ \text{to the sequence}\ a_n=25-3n:\\\\a_8=25-3(8)=25-24=1$

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What is the first step to solve for 7 − 4 = 18? *

natima [27]

A is the best answer

6 0

3 years ago

20 out of 25 students were 15 y/o, what percentage of the students is 15 ?

zalisa [80]

Answer:

80% are 15 years old

Step-by-step explanation:

To find the percent , we need to know how many out of 100

20/25

Multiply the top and bottom by 4

20*4

-----------

25*4

80/100

This is 80%

80% are 15 years old

4 0

3 years ago

Read 2 more answers

Line A passes through the points (-2, 27) and (1, -9). Line B passes through the points (-1, 15)

scZoUnD [109]

Answer:

Line A overlaps line B

Step-by-step explanation:

find gradient of both A and B and use it to find the equation of both lines

final answer will reveal that both lines are the same implying that one overlaps the other

4 0

3 years ago

The moon is about 240,000 miles from earth . What is the distance written as a whole number multiplied by a power of ten

Andreyy89

For this case we have the following number:

$240,000$

What we must do is rewrite the number as the product of two numbers.

We have then:

$240,000 = (24) (10000)$

From here, we write the number as the multiplication of a whole number and a power of base ten.

We have then:

$240,000 = (24) (10 ^ 4)$

Where,

$24$ : whole number

$10 ^ 4$ : power of base 10

Answer:

The distance written as a whole number multiplied by a power of ten is:

$(24) (10 ^ 4)$

3 0

3 years ago

Read 2 more answers

A scientist has 100 milligrams of a radioactive element. The amount of radioactive element remaining after t days can be determi

grandymaker [24]

The mass of the first shipment at time t is
$m_{1}=100( \frac{1}{2} )^{ \frac{t}{10}}$

The mass of the second shipment at time t is
$m_{2}=100( \frac{1}{2} )^{ \frac{t-3}{10} }$

At time t, the ratio of m₁ to m₂ is
$\frac{m_{1}}{m_{2}} = \frac{100}{100}. \frac{(1/2)^{t/10}}{(1/2)^{(t-3)/10}} \\ = \frac{(1/2)^{t/10}}{(1/2)^{t/10}}. \frac{1}{(1/2)^{-3/10}} \\ = (1/2)^{3/10} \\ = 0.8123$

Therefore as a percentage,
$\frac{m_{1}}{m_{2}} =100*0.8123 = 81.23 \%$

Answer: B. 81.2%

4 0

4 years ago