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Dvinal [7]
3 years ago
15

4th time posting this dont skip need help ASAP and pls hurry bc i dont have much time i will give 10 pts + brainliest

Mathematics
1 answer:
Artemon [7]3 years ago
3 0

Answer:

i think it is c but not sure

Step-by-step explanation:

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Solve each system of equations <br> 2a-3b+5c=58 <br> -5a+b-4c=-51 <br> -6a-8b+c=22
musickatia [10]

Answer:

a = 3 , b = -4 , c = 8

Step-by-step explanation:

Solve the following system:

{2 a - 3 b + 5 c = 58 | (equation 1)

-5 a + b - 4 c = -51 | (equation 2)

-6 a - 8 b + c = 22 | (equation 3)

Swap equation 1 with equation 3:

{-(6 a) - 8 b + c = 22 | (equation 1)

-(5 a) + b - 4 c = -51 | (equation 2)

2 a - 3 b + 5 c = 58 | (equation 3)

Subtract 5/6 × (equation 1) from equation 2:

{-(6 a) - 8 b + c = 22 | (equation 1)

0 a+(23 b)/3 - (29 c)/6 = -208/3 | (equation 2)

2 a - 3 b + 5 c = 58 | (equation 3)

Multiply equation 2 by 6:

{-(6 a) - 8 b + c = 22 | (equation 1)

0 a+46 b - 29 c = -416 | (equation 2)

2 a - 3 b + 5 c = 58 | (equation 3)

Add 1/3 × (equation 1) to equation 3:

{-(6 a) - 8 b + c = 22 | (equation 1)

0 a+46 b - 29 c = -416 | (equation 2)

0 a - (17 b)/3 + (16 c)/3 = 196/3 | (equation 3)

Multiply equation 3 by 3:

{-(6 a) - 8 b + c = 22 | (equation 1)

0 a+46 b - 29 c = -416 | (equation 2)

0 a - 17 b + 16 c = 196 | (equation 3)

Add 17/46 × (equation 2) to equation 3:

{-(6 a) - 8 b + c = 22 | (equation 1)

0 a+46 b - 29 c = -416 | (equation 2)

0 a+0 b+(243 c)/46 = 972/23 | (equation 3)

Multiply equation 3 by 46/243:

{-(6 a) - 8 b + c = 22 | (equation 1)

0 a+46 b - 29 c = -416 | (equation 2)

0 a+0 b+c = 8 | (equation 3)

Add 29 × (equation 3) to equation 2:

{-(6 a) - 8 b + c = 22 | (equation 1)

0 a+46 b+0 c = -184 | (equation 2)

0 a+0 b+c = 8 | (equation 3)

Divide equation 2 by 46:

{-(6 a) - 8 b + c = 22 | (equation 1)

0 a+b+0 c = -4 | (equation 2)

0 a+0 b+c = 8 | (equation 3)

Add 8 × (equation 2) to equation 1:

{-(6 a) + 0 b+c = -10 | (equation 1)

0 a+b+0 c = -4 | (equation 2)

0 a+0 b+c = 8 | (equation 3)

Subtract equation 3 from equation 1:

{-(6 a)+0 b+0 c = -18 | (equation 1)

0 a+b+0 c = -4 | (equation 2)

0 a+0 b+c = 8 | (equation 3)

Divide equation 1 by -6:

{a+0 b+0 c = 3 | (equation 1)

0 a+b+0 c = -4 | (equation 2)

0 a+0 b+c = 8 | (equation 3)

Collect results:

Answer: {a = 3 , b = -4 , c = 8

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Answer:

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