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Mariana [72]
3 years ago
15

What is the value of 3−(2/3)squared?

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0

Answer:

2  5/9

Step-by-step explanation:

3 - (2/3)^2

3 - 4/9

= 2  <u>5</u>

      9

<em>Hope this helps</em>

<em>-Amelia The Unknown</em>

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The question is incomplete. Here is the complete question.

Part A

The value of a collectible toy is increasing exponentially. The two points on the graph show the toy's initial value and its value 3 weeks afterward.

Express the toy's value t, in dollars, as a function of time w in weeks after purchase.

Part B

Write an expression to represent the toy's value 10 days after purchase

Answer and Step-by-step explanation: An exponential function is of the form: y=ab^{x}

<u>Part</u> <u>A</u>

Translating to the question, the toy's value as a function of time is

t=ab^{w}

To determine constants a and b, we use points given by graph.

First, (0,5) to find a:

5=a.b^{0}

a = 5

Now, (3,10) to determine b:

10=5b^{3}

b=\sqrt[3]{2}

b = 1.26

The toy's value as a function of time in weeks is t=5.(1.26)^{w}

<u>Part</u> <u>B</u>

Since, the function is in weeks:

1 week = 7 days

w weeks = 10 days

w = \frac{10}{7}

Replacing w:

t=5.(1.26)^{w}

t=5.(1.26)^{10/7}

Expression that represents toy's value after 10 days is t=5.(1.26)^{10/7}.

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A car costs£12500 <br> it is reduced to £11 625<br> what is the percentage decrease
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Step-by-step explanation:

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Answer:

the probability of a Type I error is 0.10

Step-by-step explanation:

  Given the data in the question;

significance level ∝ = 0.10

Null H₀ hypothesis is true;

the probability of a Type I error = ?

we know that; a type 1 error is the error of rejecting a Null hypothesis when in reality, it is true. That is false positive.

Hence, our type 1 error will be;

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Therefore, the probability of a Type I error is 0.10

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