Answer:
a)$12180.53
b)A=P(1-r)^n
Step-by-step explanation:
The formula for depreciation to use is this case is;
A=P(1-r)^n
where
A=value of boat after 5 years
P=current value of boat = $45000
r=rate of depreciation= 23% =0.23
n=time span after the boat was boat= 5 yrs
Applying the formula
A=$45000(1-0.23)^5
A=$45000(0.77)^5
A=$12180.53
Answer:
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Step-by-step explanation:
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The distance between the two schools on the map is (C) 4.2 inches.
<h3>
What is the distance?</h3>
- Distance is a numerical measurement of the distance between two objects or places.
- The distance can refer to a physical length or an estimate based on other criteria in physics or common usage.
- The distance between two points A and B is commonly expressed as |AB|.
To find the distance:
On the map,2 inches represents 5 miles.
Thus, we can write:
- 2 miles = 2 inches
- 1 mile = 2/5 inches ..... (1)
Since the actual distance between the two schools is 10.6 miles.
Multiplying both sides by 10.6 in equation (1).
- 10.6 miles = 10.6 × 2/5 = 21.2/5 = 4.24 inches.
Therefore, the distance between the two schools on the map is (C) 4.2 inches.
Know more about distance here:
brainly.com/question/17273444
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The complete question is given below:
Kim is drawing a map of the different schools in her school district. she knows that her middle school is 10.6 miles away from the middle school that her best friend attends. if every 2 inches on the map represents 5 miles, how far apart will the two schools be on the map, to the nearest tenth of an inch?
(A) 0.2 inch
(B) 0.9 inch
(C) 4.2 inches
(D) 26.5 inches
8a³
Step-by-step explanation:
(2a)³
2a×2a×2a
8a³
Answer:
5/12
Step-by-step explanation:
7/12-x=1/6
-x=1/6-7/12
-x=2/12-7/12
x=-5/12
5/12=x