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Oksana_A [137]
3 years ago
14

60 POINTS I NEED ANSWER FAST. WILL MARK BRAINLIEST.

Mathematics
2 answers:
Deffense [45]3 years ago
4 0

Answer:

5.2

Step-by-step explanation:

4.3/5.6 = 4/AB

AB = 5.2

Lina20 [59]3 years ago
4 0

Step-by-step explanation:

<em>Here</em><em>, </em>

<em> </em>

<em>Triangle</em><em> </em><em>A</em><em>D</em><em>C</em><em> </em><em>and</em><em> </em><em>triangle</em><em> </em><em>ABD</em><em> </em><em>are</em><em> </em><em>similar</em><em> </em><em>triangle</em><em> </em><em>as</em><em> </em><em>they</em><em> </em><em>are</em><em> </em><em>similar</em><em> </em><em>by</em><em> </em><em>A.A.A</em><em> </em><em>axiom</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>as</em><em> </em><em>they</em><em> </em><em>are</em><em> </em><em>similar </em><em> </em><em>their</em><em> </em><em>sides</em><em> </em><em>are</em><em> </em><em>proportional</em><em> </em><em>to</em><em> </em><em>eachother</em><em>, </em>

<em>CD</em><em>/</em><em>BD</em><em> </em><em>:</em><em> </em><em>AB</em><em>/</em><em>AC</em><em> </em><em>:</em><em> </em><em>AD</em><em>/</em><em>AD</em>

<em>4</em><em>.</em><em>3</em><em>/</em><em>4</em><em> </em><em>:</em><em> </em><em>AB</em><em>/</em><em>5</em><em>.</em><em>6</em><em> </em><em>:</em><em> </em><em>AD</em><em>/</em><em>AD</em><em>.</em>

<em>Taking</em><em> </em><em>1</em><em>st</em><em> </em><em>and</em><em> </em><em>srcond</em><em> </em><em>ratios</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>4</em><em>.</em><em>3</em><em>/</em><em>4</em><em>=</em><em>AB</em><em>/</em><em>5</em><em>.</em><em>6</em>

<em>or</em><em>,</em><em> </em><em>4AB</em><em> </em><em>=</em><em> </em><em>5</em><em>.</em><em>6</em><em>×</em><em>4</em><em>.</em><em>3</em><em> </em><em> </em><em> </em><em>(</em><em>cross</em><em> </em><em>multiplication</em><em>)</em>

<em>Therefore</em><em>, </em><em> </em><em>the</em><em> </em><em>measure</em><em> </em><em>of</em><em> </em><em>AB</em><em> </em><em>is</em><em> </em><em>6</em><em>.</em><em>0</em><em>2</em><em> </em><em>or</em><em> </em><em>6</em><em>.</em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Naddika [18.5K]

Answer:

The comparison using median and IQR is best because one of the graphs is not symmetrical.<em> </em>

Step-by-step explanation:

The following information is missing

<em>A box plot titled Number of Minutes Women Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 54, and the box ranges from 34 to 50. A line divides the box at 48.  </em>

<em>A box plot titled Number of Minutes Men Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 68, and the box ranges from 36 to 60. A line divides the box at 48.  </em>

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<em>The comparison would be more accurate using the mean and MAD because one of the graphs is symmetric. </em>

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Mean and MAD are useful for comparison when both data sets are symmetrical.

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Angelina_Jolie [31]

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Step-by-step explanation:

s = 5x + 3y

There is an answer

The rest of the equation that has no substituted delta is not true, so the prime variables have relative extremes.

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