a pizza place charges $15 for a pepperoni pizza and $12 for a cheese pizza. the goal is to sell $540 in pizza for the day. The s

Question

3 years ago

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a pizza place charges $15 for a pepperoni pizza and $12 for a cheese pizza. the goal is to sell $540 in pizza for the day. The s

ituation can be represented by the equation 15x+12y=540, x=pepperoni pizzas and y= cheese pizzas. If the pizza place runs out of pepperoni, how many cheese pizzas must be sold to reach the daily goal?

Mathematics

1 answer:

Ede4ka [16] · Answer 1 · 2022-07-21T19:53:52+03:00

The pizza place should sell 45 cheese pizza in order to reach daily goal.

Step-by-step explanation:

Let, x=pepperoni pizzas and y= cheese pizzas.

And 15x+12y=540

If pizza place runs out of pepperoni pizza, then x=0 we need to find how many cheese pizza (y) must be sold to achieve the goal.

Putting x=0 and finding y,

$15x+12y=540\\15(0)+12y=540\\12y=540\\y=\frac{540}{12} \\y=45$

So, The pizza place should sell 45 cheese pizza in order to reach daily goal.

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