Ask question

Ask question

All categories

4 years ago

8

Consider the equation x+2y=8.Part A: How many solutions does this equation have? Part B: What are three solutions to this equati

on? Part C: Represent the solutions to this equation on the graph.

1 answer:

natita [175]4 years ago

7 0

Answer:

Determine what each letter represents in the Punnett square.

Letters A and B represent the genotypes of the .

Letters C, D, E, and F represent the genotypes of the .

Step-by-step explanation:

You might be interested in

Each guest at casandras party had 3 turns to act out worlds during a game. They began with a list of 50 words. When they finishe

Veronika [31]

Answer:

16 fits but not evenly

Step-by-step explanation:

16 times 3 equals 48 and 17 times 3 equal is 51 so someone didnt go 3 times.

7 0

3 years ago

At a football stadium, 10% of the fans in attendance were teenagers. If there were 330

pishuonlain [190]

Answer: 3300 teenagers

Step-by-step explanation:

10/100

330/x

After you cross multiply then divide, x equals 3300.

8 0

3 years ago

A ball is dropped from a height of 30 feet and each time it hits the ground it bounces 0.75 of the previous height. What is the

dimulka [17.4K]

30 x 0.75 = 22.5 .............(1st)

22.5 x 0.75 = 16.875 ......(2nd)

16.875 x 0.75 = 12.66 ....(3rd)

ANSWER: C) 12.66

8 0

4 years ago

Find the perimeter of triangle ABC.

Harlamova29_29 [7]

By definition, the perimeter of the triangle is the sum of its sides.
We must then use the formula of distance between points:
$d = \sqrt{(x2-x1) ^ 2 + (y2-y1) ^ 2}$
We now look for the longitus for each of the sides:

For L1:
$L1 = \sqrt{(6-2)^2 + (6-2)^2}$
$L1 = \sqrt{32} 
$
$L1 = 4\sqrt{2}$

For L2:
$L2 = \sqrt{(7-2)^2 + (-3-2)^2}$
$L2 = \sqrt{50}$
$L2 = 5\sqrt{2}$

For L3:
$L3 = \sqrt{(7-6)^2 + (-3-6)^2}$
$L3 = \sqrt{82}$

Then, the perimeter is given by:
P = L1 + L2 + L3
Substituting values we have:
$P = 4\sqrt{2} + 5\sqrt{2} + \sqrt{82} 

P = 9\sqrt{2} + \sqrt{82}$

Answer:
the perimeter of triangle ABC is:
none of the above.

5 0

4 years ago

Read 2 more answers

A devastating freeze in California's Central Valley in January 2007 wiped out approximately 75% of the state's citrus crop. It t

solniwko [45]

The relationship between the percentage of frozen citrus crop, and the cost of box of oranges is an illustration of a linear function.

<em>The linear equation of the function is: </em> $g(P) = 22.9P+7$ <em>.</em>
<em>The inverse function is: </em> $g^{-1}(c) = \frac{1}{22.9}(c - 7)$ <em> .</em>
<em>A practical domain is from 0% to 100%</em>
<em>A practical range is from 7 to 29.9 </em>

<u>A. Input quantity</u>

The input quantity is the percentage of frozen citrus crop

<u />

<u>B. Output quantity </u>

The output quantity is the cost of box of oranges

<u>C. The linear function</u>

We have:

$(P_1,c_1) = (20\%,11.58)\\(P_2,c_2) = (80\%,25.32)$

<em>Calculate the slope of the function</em>

$m = \frac{c_2 - c_1}{P_2 - P_1}$

$m = \frac{25.32 - 11.58}{80\%-20\%}$

$m = \frac{13.74}{60\%}$

$m = 22.9$

<em>The linear equation is calculated as follows:</em>

$c -c_1 = m(P-P_1)$

$c -11.58= 22.9(P-20\%)$

$c-11.58 = 22.9P-4.58$

<u>D. Rewrite as y = mx + b</u>

We have:

$c-11.58 = 22.9P-4.58$

Collect like terms

$c = 22.9P - 4.58 + 11.58$

$c = 22.9P+7$

<em>The function is:</em>

$g(P) = 22.9P+7$

<u>E. A practical domain</u>

The domain is the possible values of P. Because P is a percentage, its possible values are 0% to 100%.

The domain of the function is: $[0\%,100\%]$

<u>F. A practical range</u>

When P = 0%

$c = 22.9 \times 0\% + 7 = 7$

When P = 100%

$c = 22.9 \times 100\% + 7 = 29.9$

Hence, the range of the function is: $[7,29.9]$

G. The meaning of $g^{-1}(12)$

The inverse function of g(P) is $g^{-1}(P)$

So:

$g^{-1}(12)$ is the percentage of frozen citrus crop, when the cost is $12.

<u>H. The inverse formula</u>

We have:

$c = 22.9P+7$

Subtract 7 from both sides

$c - 7 = 22.9P$

Make P the subject

$P = \frac{1}{22.9}(c - 7)$

So, the inverse formula is:

$g^{-1}(c) = \frac{1}{22.9}(c - 7)$

Substitute 12 for c

$g^{-1}(12) = \frac{1}{22.9}(12 - 7)$

$g^{-1}(12) = \frac{1}{22.9} \times 5$

$g^{-1}(12) = 22\%$

Read more about linear equations at:

brainly.com/question/19770987

6 0

3 years ago