Answer:
In the F1 generation
RR = 0%
Rr = 50% (or 0.5)
rr = 50% (or 0.5)
Explanation:
A pink flowering plant has the genotype Rr. It is heterozygous for the allele. The alleles for this gene appears to show incomplete dominance, as the heterozygous phenotype is a blend of the two homozygous genotypes.
A white flowering plant has the genotype rr. It is homozyogous for the white allele
A punnet square of the cross is shown.
The resulting punnet square shows that only Rr and rr genotypes are possible, at a ratio of 50:50 (or 1:1). Therefore, the genotype frequency of Rr is 50%, and rr is 50% in the F1 generation. This can also be written as 0.5. It is not possible to get a red plant, as the genotype RR can not come from this cross
Answer: Indeed, one of the best I've seen!
Explanation:
A. Is the correct answer :)
Answer No 1:
The set up of the punnet square is shown in the attached diagram. As the alleles assort independently hence the gametes formed will be OT,Ot,OT,Ot and OT,Ot,oT,ot. These will be the outcomes of the possible gametes formed. When these gametes are cross bred, the results are shown in the diagram attached.
Answer No 2:
The outcomes of each possible genotype are:
OOTT = 2/16
OOTt = 4/16
OOtt = 2/16
Oott = 2/16
OoTT = 2/16
OoTt = 4/16
Answer No 3:
The likelihood of each possible offspring phenotype is:
Orange petals with tall stem and orange petals with small stems present in ratio 12:4 i.e. 3:1.
A because they can eat out of the trash where the others require thenforest to live. Hope this helped.
