Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Answer:
the value is ones.
Step-by-step explanation:
6=hundred 5= tens and the 6 u are talking about is = ones
Answer:
3 cars
Step-by-step explanation:
4 times 3 is 12
Answer:
equation
Step-by-step explanation:
obviously!
Answer: (2,-1)
Solution:
The critical points of a function are those where the first derivative is zero.
Find the first derivative of f(x), d f(x) / dx
1) Given: f(x) = -x^2 + 4x - 5.
2) d f(x) / dx = d [ - x^2 + 4x - 5] / dx = -2x + 4
3) Equal d f(x) / dx to 0
d f(x) / dx = -2x + 4 = 0 => 2x = 4, => x = 2
4) Replace 2 in the function f(x)
f(2) = - (2)^2 + 4(2) - 5 = - 4 + 8 - 5 = - 1
5) Answer: point ( 2, -1)