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pshichka [43]
4 years ago
8

Can someone please help me with this question?

Mathematics
1 answer:
earnstyle [38]4 years ago
8 0

Check the picture below.

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Use the function rule to complete the table<br> -10x + y = 4
alexgriva [62]
Plug in the given numbers (x) to the equation. For example, let's take the first value it gives us. -10(-2) +y=4 20+y=4 y=-16 Then you would put that on the table, and plug in the next value(s). Hope this helped!
8 0
3 years ago
Read 2 more answers
Rita runs 6 miles in 44 minutes. At the same rate, how many minutes would she take to run 9 miles?
kherson [118]

You run 0.5 miles every 3 minutes => 1 mile every 6 minutes. Your friend runs 2 miles every 14 minutes => 1 mile every 7 minutes. You run a whole number of miles every number of minutes that is a multiple of 6. Your freind runs a whole number of miles every number of minutes that is a multiple of 7 Then the least possible number of miles that you both run to end at the same time is the least common factor of 7 and 6 minutes. This is 7 * 6 = 42 minutes. You will have run 42 min / (6 miles/min) = 7 miles, and your friend will have run 42 min / (7 miles/min) = 6 miles




5 0
3 years ago
Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are
jasenka [17]

Answer:

The indicated confidence interval for the difference between the two population means is  (-1.5159, 7.5159)

Step-by-step explanation:

Let the drying times of type A be the first population and the drying times of type B be the second population. Then

We have small sample sizes n_{1} = 11 and n_{2} = 9, besides \bar{x}_{1} = 71.5, s_{1} = 3.4 , \bar{x}_{2} = 68.5 and s_{2} = 3.6. Therefore, the pooled

estimate is given by  

s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(11-1)(3.4)^{2}+(9-1)(3.6)^{2}}{11+9-2} = 12.1822

The 99% confidence interval for the true mean difference between the mean drying time of type A and the mean drying time of type B is given by

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{11}+\frac{1}{9}}, i.e.,

(71.5-68.5)\pm t_{0.005}(3.4903)\sqrt{\frac{1}{11}+\frac{1}{9}}

where t_{0.005} is the 0.5th quantile of the t distribution with (11+9-2) = 18 degrees of freedom. So

3\pm(-2.8784)(3.4903)(0.4495), i.e.,

the indicated confidence interval for the difference between the two population means is  (-1.5159, 7.5159)

5 0
3 years ago
How do u write d dozen eggs in a numerical or varoable expression?
FromTheMoon [43]
<span>Numeral expression is composed of numeric constants and operation while variable expression consist of both numeric and variables constants.
d dozen of eggs converted to numerical or variable expression:
 =>  There are 12pieces of eggs in 1 dozen, so that is 12x1=12
 => Therefore, the numerical value is 12 x d or simply 12d </span>



7 0
4 years ago
Find the measure of x.<br> 40<br> 45°<br> x = [?]<br> Round to the nearest tenth.
MAXImum [283]

L=40×Tan45

=40

x²=root(40²-40²)

=0

3 0
3 years ago
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