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Mariana [72]
3 years ago
9

57+16 is the same as 60+

Mathematics
2 answers:
navik [9.2K]3 years ago
5 0

Answer:

57+16 is the same as 60+13

Step-by-step explanation:

Allushta [10]3 years ago
4 0

Answer:

57+16 is the same as 60+13

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Helppp how do u do 12
Delicious77 [7]
B is the correct answer



\frac{x}{100}  =  \frac{53}{106}  \\ x =  \frac{53 \times 100}{106}  =  \frac{5300}{106}  = 50




good luck
4 0
3 years ago
Read 2 more answers
Help please in the photo
Arada [10]

Answer:

m = 40

Step-by-step explanation:

The triangle inside the circle has 2 equal sides ( the radii ) of the circle, thus

The base angles are congruent both 50°

The 3 angles on the tangent sum to 180°, so

m + 50 + 90 = 180

m + 140 = 180 ( subtract 140 from both sides )

m = 40

5 0
3 years ago
On Sunday, a local hamburger shop sold a combined total of 428 hamburgers and cheeseburgers. The number of cheese burgers sold w
melisa1 [442]
The equation you can use is x + 3x = 428 with x as the number of cheeseburgers and 3x the number of hamburgers 
you solve for x and get 4x= 428 and x=107

so 321 hamburgers were sold that day.
5 0
3 years ago
A poll agency reports that 75% of teenagers aged 12-17 own smartphones. A random sample of 234 teenagers is drawn. Round your an
GalinKa [24]

Answer:

If our random variable of interest for this case is X="the number of teenagers between 12-17 with smartphone" we can model the variable with this distribution:

X \sim Binom(n=234, p=0.75)

And the mean for this case would be:

E(X) =np = 234*0.75= 175.5

And the standard deviation would be given by:

\sigma =\sqrt{np(1-p)}= \sqrt{234*0.75*(1-0.75)}= 6.624

Step-by-step explanation:

If our random variable of interest for this case is X="the number of teenagers between 12-17 with smartphone" we can model the variable with this distribution:

X \sim Binom(n=234, p=0.75)

And the mean for this case would be:

E(X) =np = 234*0.75= 175.5

And the standard deviation would be given by:

\sigma =\sqrt{np(1-p)}= \sqrt{234*0.75*(1-0.75)}= 6.624

3 0
3 years ago
(3n² p⁴)<br> Idk how to solve it
tester [92]

me neither but this is what i got


3n² p⁴


4 0
3 years ago
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