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3 years ago

What is 28,000 have in common with 27,000

Mathematics

2 answers:

ratelena [41]3 years ago

8 0

They are both in the ten thousands place

xeze [42]3 years ago

6 0

They both have 3 zeros and into the tens place

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Suppose monthly rental prices for a one-bedroom apartment in a large city has a distribution that is skewed to the right with a

omeli [17]

Answer:

a) Nothing, beause the distribution of the monthly rental prices are not normal.

b) 1.43% probability that the sample mean rent price will be greater than $900

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

(a) Suppose a one-bedroom rental listing in this large city is selected at random. What can be said about the probability that the listed rent price will be at least $930?

Nothing, beause the distribution of the monthly rental prices are not normal.

(b) Suppose a random sample 30 one-bedroom rental listing in this large city will be selected, the rent price will be recorded for each listing, and the sample mean rent price will be computed. What can be said about the probability that the sample mean rent price will be greater than $900?

Now we can apply the Central Limit Theorem.

$\mu = 880, \sigma = 50, n = 30, s = \frac{50}{\sqrt{30}} = 9.1287$

This probability is 1 subtracted by the pvalue of Z when X = 900.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{900 - 880}{9.1287}$

$Z = 2.19$

$Z = 2.19$ has a pvalue of 0.9857

1 - 0.9857 = 0.0143

1.43% probability that the sample mean rent price will be greater than $900

8 0

3 years ago

Use the following diagram and information to answer the question.

Reika [66]

Answer:

b) Julie can use properties of congruent triangles to show that AB≅BC and BC≅CD. Then she can show BC≅AD because opposite sides of a parallelogram are congruent

Step-by-step explanation:

On the assumption that Julie must show all four sides to be congruent, the one remaining step after using the properties of congruent triangles is to show that side AD is congruent to the rest of the sides. Answer choice B describes that.

___

IMO, Julie is finished after she shows∠A≅∠B and AB≅BC, because a parallelogram will be a square if adjacent sides are congruent (makes it a rhombus) and adjacent angles are congruent (makes it a rectangle). A rhombus that is a rectangle is a square.

8 0

3 years ago

The price of a four-star meal, only $5050 per couple decades ago, has since increased 400400%. The current price of a four-

Vikentia [17]

Answer:

The correct answer is C.

Step-by-step explanation:

The price of a four-star meal, only $50 per couple decades ago, has since increased 400%.

This means that if the $50 per couple is 100%(decimal 1), the current price is 100%+400% = 500%(decimal 5). So we can solve a rule of three to find the current price of a four-star meal.

1 - 50

5 - x

$x = 50*5$