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3 years ago

Simplify the fraction. 25/45

Mathematics

2 answers:

Ipatiy [6.2K]3 years ago

7 0

Answer:

5/9

Step-by-step explanation:

divide 25 by 5 and 45 by 5

Zepler [3.9K]3 years ago

7 0

Answer:

5/9

Step-by-step explanation:

find the common divisor for both the numerator and denominator.

25 and 45 could be divided by 5, so divide both by 5

$\frac{25}{45}$ ÷ $\frac{5}{5}$ = $\frac{5}{9}$

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3 years ago

He temperature was -13 degrees and then rose 9 degrees.<br> -13 + 9<br> 13 + 9<br> 9 - (-13)

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3 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

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2 years ago